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kipiarov [429]
2 years ago
7

An oil droplet is levitated and held at rest in a region where the electric field is 1.4x104 N/C directed vertically downwards.

If the droplet has 3 excess electrons attached, what is its mass
Physics
1 answer:
Ratling [72]2 years ago
8 0

W = m g     weight of drop

W = q E

m = q E / g = = 3 e E / g

m = 3 * 1.6E-19 * 1.4E4 / 9.8 = 6.96E-16 kg

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An ideal solenoid having a coil density of 5000 turns per meter is 10 cm long and carries a current of 4.0
Diano4ka-milaya [45]
The rule that is used to get the strength of magnetic field at the center of solenoid (B) is:
B = <span>µ x n x I where:
</span>µ is the permeability of the medium where the solenoid is based. In this problem, the medium is air which means that µ = <span>µ </span><span>o = 4 pi x 10^-7 Tm/A
</span>I is the current passing (I = 4 amperes)
n is the number of turns per unit length (5000 turns)

Substituting in the mentioned equation, we find that:
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3 years ago
A small apple weighs 0.8N. How much would an apple that is 4 times as massive weigh?
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Answer:

W=31.99 N

Explanation:

W= 8 N (N= kg*m/ s^2)

W= m* g

8 N= m * 9.8 m/s^2

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W= mg

= (3.264 kg)(9.8 m/s^2)

W=31.99 N

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How does an atom change if all of its electros are removed?
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The atom becomes positively charged.

EXPLANATION :

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Hence, the correct answer is that atom will be positively charged.

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