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kari74 [83]
3 years ago
9

Plz I need a help expand:(5x+4y)(5x-4y) ​

Mathematics
1 answer:
arlik [135]3 years ago
8 0

Answer:

25xwith an exponent of 2 minus 16y with an exponent of 2

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What is 8 1/3 x 3/5?
Savatey [412]
8\frac{1}{3}\times\frac{3}{5}=\frac{8\times3+1}{\not3_1}\times\frac{\not3^1}{5}=\frac{24+1}{1}\times\frac{1}{5}=\frac{25}{1}\times\frac{1}{5}=\frac{25}{5}=\boxed5
7 0
3 years ago
Identify if the proportion is true or false. 4 to 11 = 12 to 33.
yuradex [85]

Answer:

True

Step-by-step explanation:

Take 4/11 and you get 0.363636363636, which is the same if you take 12/33.  So the proportion of the two is the same.

6 0
3 years ago
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Help me please will mark brainlyist
Leni [432]

Answer:

24.46

Step-by-step explanation:

4 0
3 years ago
Find \tan\left(\frac{17\pi}{12}\right)tan( 12 17π ​ )tangent, left parenthesis, start fraction, 17, pi, divided by, 12, end frac
uranmaximum [27]

One way to do this is to notice

\dfrac{17\pi}{12}=\dfrac\pi6+\dfrac{5\pi}4

Then

\tan\dfrac{17\pi}{12}=\tan\left(\dfrac\pi6+\dfrac{5\pi}4\right)=\dfrac{\tan\frac\pi6+\tan\frac{5\pi}4}{1-\tan\frac\pi6\tan\frac{5\pi}4}

We have

\tan\dfrac\pi6=\dfrac{\sin\frac\pi6}{\cos\frac\pi6}=\dfrac{\frac12}{\frac{\sqrt3}2}=\dfrac1{\sqrt3}

and since \tan x has a period of \pi,

\tan\dfrac{5\pi}4=\tan\left(\pi+\dfrac\pi4\right)=\tan\dfrac\pi4=1

and so

\tan\dfrac{17\pi}{12}=\dfrac{\frac1{\sqrt3}+1}{1-\frac1{\sqrt3}}=\dfrac{1+\sqrt3}{\sqrt3-1}=2+\sqrt3

7 0
3 years ago
ASAP!!! Please answer!!
Ronch [10]

Answer:

x=8g/3(k+d)

Step-by-step explanation:

Move all terms to the left side and set equal to zero. Then set each factor equal to zero.

Hope this helps

6 0
3 years ago
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