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Maksim231197 [3]
3 years ago
13

What shape would have a cross section that could match that of a sphere?

Mathematics
1 answer:
lapo4ka [179]3 years ago
3 0
Cross sections of spheres are cicles. Therefore, if cut parallel to the ends, CYLINDER also has cross sections that match that of a circle.
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Determine if the following relation represents a function or not.
artcher [175]

Answer:

It is a function.

Step-by-step explanation:

Functions are relations in which one domain value is assigned to exactly one range value. The x-value must not repeat in the relation set for it to be a function.

{(2,3), (4,3), (6,3), (5,9), (3,9)}

There are no repeating x-values given.

The relation should be a function.

Hope this helps.

6 0
3 years ago
Find the x and y intercepts 5y + 3x = 15
Tomtit [17]
First, find the x-intercept.

The x-intercept will be at the point (x, 0) where x is any real number. If we substitute the x-coordinate and the y-coordinate for the x and y variables in the equation, we can solve for x.

5y + 3x = 15
5(0) + 3x = 15
3x + 15
x = 5

We found the x-intercept now find the y-intercept with the same process.

The y-intercept will be at the point (0, y) where y is any real number.

5y + 3x = 15
5y + 3(0) = 15
5y = 15
y = 3

So, the x-intercept is (5, 0) and the y-intercept is (0, 3)
8 0
3 years ago
If angle vuw = 4x+6 and wut = 6x+10 what is the measure of wut
Damm [24]

Answer:

C, 38°

Step-by-step explanation:

ray UW is the angle bisector of ∠VUT

--> m∠VUW = m∠WUT = 1/2 m∠VUT

<=> 4x + 6 = 6x - 10

<=> 6 + 10 = 6x - 4x

<=> 2x = 16

<=> x = 8

So, the measure of m∠WUT is: 6x - 10 = 6 . 8 - 10 = 48 - 10 = 38°

4 0
3 years ago
What is the equation written in vertex form of a parabola with a vertex of (–1, 8) that passes through (1, 0)?
Archy [21]

Answer:

y = -2(x + 1)^2 + 8

Step-by-step explanation:

The equation of a parabola can be written in the form;

y = a(x-h)^2 + k

where a is the multiplier (h,k) is the vertex

so h = -1 and k = 8

Plug in these values

y = a(x + 1)^2 + 8

So to get the value of a, we use the point where the parabola passes through which is the point (1,0)

Simply substitute the values of x and y

0 = a(1 + 1)^2 + 8

0 = a(2)^2 + 8

-8 = 4a

a = -8/4

a = -2

So therefore the equation of the parabola is ;

y = -2(x + 1)^2 + 8

7 0
3 years ago
In the triangle below, suppose that m/Q = (2x-3)°, m/R= (5x+7)°, and m/S=xº.
o-na [289]

Answer:

Please Attach The Pic so someone can answer.....

Step-by-step explanation:

7 0
2 years ago
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