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3 years ago

What is the perimeter of triangle ABC?

Mathematics

1 answer:

kolbaska11 [484]3 years ago

6 0

Step-by-step explanation:

Here

A(-2,6)
B(1,2)
C(-2,-2)

Now,

$\\ \tt\hookrightarrow AB=\sqrt{(-2-1)^2+(6-2)^2}$

$\\ \tt\hookrightarrow AB=\sqrt{(-3)^2+(4)^2}$

$\\ \tt\hookrightarrow AB=\sqrt{9+16}$

$\\ \tt\hookrightarrow AB=\sqrt{25}=5units$

And,

$\\ \tt\hookrightarrow BC=\sqrt{1+2)^2+(2+2)^2}$

$\\ \tt\hookrightarrow BC=\sqrt{(3)^2+(4)^2}$

$\\ \tt\hookrightarrow BC=\sqrt{9+16}$

$\\ \tt\hookrightarrow BC=\sqrt{25}=5units$

And

$\\ \tt\hookrightarrow AC=\sqrt{(-2+2)^2+(6+2)^2}$

$\\ \tt\hookrightarrow AC=\sqrt{(0)^2+(8)^2}$

$\\ \tt\hookrightarrow AC=\sqrt{8^2}=\sqrt{64}=8units$

Now

$\\ \tt\hookrightarrow perimeter=5+5+8=18units$

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Which of the following is a solution to this inequality? y>1/2x+2

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Mr. Morales purchases supplies for his classroom and the science department. Mr. Morales purchases 6 boxes of pencils, 12 boxes

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Answer:

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Step-by-step explanation:

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3 years ago

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For each function, do the following: a) state the name of the function, b) identify the independent and dependent variable, c) i

daser333 [38]

<h2>Hello</h2>

The answers are:

a) The name of the function is g, and it's an Exponential Function.

b) Independent variable : x , dependent variable : g(x)/y

c) The rule that assigns exactly one output to the very input is called "function".

d) $g(4)=2^{4}+12=16+12=28$

Usually, the name of a function (g(x)) is given by letter that is out of the parentheses. For this exercise, the name of the function is "g", and it's an Exponential Function.

The independent variable of a function is the variable we assign the different values. For this exercise, the independent variable is designated with the letter "x".

The dependent variable is the function itself (g(x)), it's also called "y", and it's called "dependent" variable because its values will always depend on the "independent variable".

A function is the rule that states that there is exactly one output (range value) to the each input (domain value). A function only exists when there is exactly one output value (range) for each input (domain), if there is more than one output for each input, the function does not exist.

To evaluate a function we need to assign values to the independent variable(x), therefore:

$g(4)=2^{4}+12=16+12=28$

Have a nice day!

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3 years ago

The zeros of the function f(x)=(x+2)^2 - 25 are?

zloy xaker [14]

Zeros of the function
f(x) = (x + 2)² - 25
f(x) = (x + 2)(x + 2) - 25
f(x) = x(x + 2) + 2(x + 2) - 25
f(x) = x(x) + x(2) + 2(x) + 2(2) - 25
f(x) = x² + 2x + 2x + 4 - 25
f(x) = x² + 4x + 4 - 25
f(x) = x² + 4x - 21
x² + 4x - 21 = 0
x = -(4) +/- √((4)² - 4(1)(-21))
 2(1)
x = -4 +/- √(16 + 84)
 2
x = -4 +/- √(100)
 2
x = -4 +/- 10
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x = -2 + 5
x = -2 + 5 x = -2 - 5
x = 3 x = -7
f(x) = x² + 4x - 21
f(3) = (3)² + 4(3) - 21
f(3) = 9 + 12 - 21
f(3) = 21 - 21
f(3) = 0
(x, f(x)) = (3, 0)
or
f(x) = x² + 4x - 21
f(-7) = (-7)² + 4(-7) - 21
f(-7) = 49 - 28 - 21
f(-7) = 21 - 21
f(-7) = 0
(x, f(x)) = (-7, 0)

Vertex
X - Intercept
-b/2a = -(4)/2(1) = -4/2 = -2

Y - Intercept
y = x² + 4x - 21
y = (-2)² + 4(-2) - 21
y = 4 - 8 - 21
y = -4 - 21
y = -25
(x, y) = (-2, -25)

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