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3 years ago

Which of the following is the solution set to the equation: 2x(x-3)(4x+1)=0?

Mathematics

1 answer:

Troyanec [42]3 years ago

3 0

Answer:

(1) {-1/4, 0, 3}

Step-by-step explanation:

Step 1: Factor left side of equation.

2x(4x+1)(x−3)=0

Step 2: Set factors equal to 0.

2x=0 or 4x+1=0 or x−3=0

x=0 or x= −1/4 or x=3

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A person aiming at a target receives 10 points if their shot is within 1 inch of the target, 5 points if it is between 1 and 3 i

Gelneren [198K]

Answer:

standard deviation is 2.886 [expected points]

Step-by-step explanation:

Let x is number of points scored so that given target uniformly dstributed between 0 and 10

clearly X uniform(0,10)

mean is defined as $E(x) = \frac{a+b}{2}$

$\frac{0+10}{2} = 5$

we know that variance is given as $\frac{(b-a)^2}{12}$

$V(x) = \frac{(b-a)^2}{12}$

$\frac{(10-0)^2}{12}$

= 8.333

therefore standard deviation is $\sqrt{V(x)} = \sqrt{8.333}$

standard deviation is 2.886 [expected points]

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3 years ago

An experiment consists of dealing 7 cards from a standard deck of 52 playing cards. What is the probability of being dealt exact

In-s [12.5K]

Answer: 0.00153

Step-by-step explanation:

Given: An experiment consists of dealing 7 cards from a standard deck of 52 playing cards.

Number of ways of dealing 7 cards from 52 cards = $^{52}C_7$

Since there are 13 clubs and 13 spades.

Number of ways of getting exactly 4 clubs and 3 spades= $^{13}C_4\times\ ^{13}C_3$

Now, the probability of being dealt exactly 4 clubs and 3 spades

$=\dfrac{^{13}C_4\times\ ^{13}C_3}{^{52}C_7}\\\\\\=\dfrac{{\dfrac{13!}{4!(9!)}\times\dfrac{13!}{3!10!}}}{\dfrac{52!}{7!45!}}\\\\=\dfrac{715\times286}{133784560}\\\\=0.00152850224271\approx0.00153$

Hence, the probability of being dealt exactly 4 clubs and 3 spades = 0.00153

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3 years ago

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Answer:

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Step-by-step explanation:

9.89-6.35=3.54

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