The probability that the number chosen is divisible by 5 is; 1/5.
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What is the probability that the number chosen is divisible by 5?</h3>
It follows from the task content that the number of possible outcomes in the probability event is; 100. Additionally, the number of required outcomes is 20 as only 20 numbers are divisible by 5.
Ultimately, the required probability is; 20/100 = 1/5.
Read more on probability;
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$SPJ1
21(3a-2b) hope this help !
I’m sorry if I’m wrong
Answer:
a) 279 b)254
Step-by-step explanation:
Mean = 269 days
standard deviation = 8 days
let n be the pregnancy lenght.
using normal distribution formula
z = (n – mean)/ standard deviation
n = z * standard deviation + mean
Now, z values for the top 12% has to be found using a z table.
The top 12% means 88% of area under the curve. In this case z = 1,176
n = 1,176 * 8 + 269
n = 278.4 = 279
The bottom 3% means 97% of area under the curve. In this case z = -1,882
n = -1,882 * 8 + 269
n = 253.94 = 254
0.097- or it could be 0.10 if you round it
