Let the breadth be x
length=x+8
according to the question
area of the pool = l*b
105=x*x+8
if u solve this equation further u will get the answer
Recall the secant-tangent theorem, and you have
EA^2 = EC*CD
12^2 = 8*(x+10)
and now ED = EC+CD = 8+x+10
I suspect a typo somewhere in the murk above
Answer:
(18 x 4) * 5 = 360
(18 x 4) * 5 = 1320
15 x (4 x 20) = 1200
Step-by-step explanation:
<span>you know the measure of AC that is 4 and the measure of AB that is 4. Then you do the theorem of Pythagoras 4 squared + 4 squared = hypotnuza (CB)
</span>
then + all sides
You multiply the two side lengths for area
To get 52x^3y
To find perimeter you add all the side lengths to get 8x^2+26x
