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Mumz [18]
3 years ago
12

Through any two points, there exists one and only one line. t/f

Mathematics
1 answer:
Alex777 [14]3 years ago
8 0
True if the points are on a flat plane. If it's a curved surface, then no.
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Drag expressions to complete each equation.
Maru [420]

Answer:

see explanation

Step-by-step explanation:

Using the rules of exponents

a^{b} × a^{c} = a^{b+c}

\frac{a^{b} }{a^{c} } = a^{b-c}

a^{c} × b^{c} = (ab)^{c}

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What is a discrete function?
IgorLugansk [536]

Answer:

A discrete function is a function with distinct and separate values. This means that the values of the functions are not connected with each other (this will be shown as a bunch of points that are not connected together).

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2 years ago
Mr. Nelson bought a car for $20,000 with a 5% interest rate.
LekaFEV [45]

Answer:

A ) Hence The interest for the car loan is $ 4,310

B ) Hence The interest for the car loan is $ 3,152

Step-by-step explanation:

Given as :

The loan for the car = $ 20,000

The rate of interest of car loan = 5 % compounded annually

A ) The period of loan = 48 months = 4 years

Let the interest of the loan = CI

<u>From compounded method</u>

Amount = Principal × (1 + \frac{\textrm Rate}{100})^{\textrm time}

Or, Amount = $ 20,000 × (1 + \frac{\textrm 5}{100})^{\textrm 4}

Or,  Amount = $ 20,000 × (1.05)^{4}

Or, Amount = $ 20,000 × 1.2155

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∴  CI = $ 4,310

Hence The interest for the car loan is $ 4,310

B ) The loan for the car = $ 20,000

The rate of interest of car loan = 5 % compounded annually

The period of loan = 3 years

Let the interest of the loan = CI

So,

<u>From compounded method</u>

Amount = Principal × (1 + \frac{\textrm Rate}{100})^{\textrm time}

Or, Amount = $ 20,000 × (1 + \frac{\textrm 5}{100})^{\textrm 3}

Or,  Amount = $ 20,000 × (1.05)^{3}

Or, Amount = $ 20,000 × 1.1576

∴ Amount = $ 23,152

So, Interest = Amount - Principal

Or, CI = $ 23,152 - $ 20,000  

∴  CI = $ 3,152

Hence The interest for the car loan is $ 3,152

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3 years ago
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Answer:

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Step-by-step explanation:

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4. Misty drew trapezoid FGHK with the vertices F(-3, 2), G(-3, 6), H( 1, 4) and K(1,2). She also drew
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