Write the name for the compound Al₂S₃

horsena [70]

<h3>Sodium chloride and Sodium bicarbonate are ionic substances</h3><h3>Further explanation </h3>

Atoms have different stability. Unstable atomic atoms will try to form stable electron configurations like those of noble gases. Where noble gases have the number of outer electrons 2 or 8

The formation of electron configurations such as noble gases can be done by sharing electrons with covalent bonds or hand over electrons with ionic bonds

Generally, ionic bonds occur in metals and nonmetallic elements.

While covalent bonds occur because of the use of shared electrons. In general, this bond occurs between nonmetallic elements, which has the same electron attraction

Characteristics of ionic compounds include: solid / crystalline form, soluble in water, conduct electricity

Let see the answer choices

Oil

It is a covalent compound because part of the hydrocarbon, a liquid that forms a bond between elements C, H and O, and does not dissolve in water (floats on water)

Cornstarch

Obtained from corn which contains glucose which is a carbohydrate. It does not dissolve in water. Contains a bond between C, H and O. Includes covalent compounds

Sodium chloride
Sodium bicarbonate

Both are ionic compounds, soluble in water, in solid form

NaCl ⇒ Na⁺ + Cl⁻

NaHCO₃⇒ Na⁺ + HCO₃⁻

<h3>Learn more </h3>

ionic bonding

brainly.com/question/1603987

Type of atoms typically form covalent bonds

brainly.com/question/13648552

the ionic compound LiI

brainly.com/question/2732123#

Keywords : ionic, covalent, Oil ,Cornstarch ,Sodium chloride,Sodium bicarbonate

#LearnWithBrainly

6 0

3 years ago

Read 2 more answers

Standard reduction half-cell potentials at 25∘c half-reaction e∘ (v) half-reaction e∘ (v) au3 (aq) 3e−→au(s) 1.50 fe2 (aq) 2e−→f

Zanzabum

<em>K</em> = 5.0 × 10^25

<h2>Part (a). Calculate <em>E</em>° for the reaction </h2>

<em>Step 1.</em> Write the equations for the two half-reactions

2H^(+)(aq) + 2e^(-) → H2(g); _0.00 V

Zn^(2+)(aq) + 2e^(-) → Zn(s); -0.76 V

<em>Step 2.</em> Identify the cathode and the anode

The half-cell with the more negative <em>E</em>° (Zn) is the anode.

<em>Step 3.</em> Calculate <em>E</em>°

Zn(s) → Zn^(2+)(aq) + 2e^(-); _________+0.76 V

2H^(+)(aq) + 2e^(-) → H2(g); __________0.00 V

Zn(s) + 2H^(+)(aq) → Zn^(2+)(aq) + H2(g); +0.76 V

<em>E</em>° = +0.76 V

<h2>Part (b). Calculate <em>K</em> for the reaction </h2>

The relation between <em>E</em>° and <em>K</em> is

where

<em>R</em> = the universal gas constant: 8.314 J·K^(-1)mol^(-1)

<em>T</em> = the Kelvin temperature

<em>n</em> = the moles of electrons transferred

<em>F</em> = the Faraday constant: 96 485 J·V^(-1)mol^(-1)

Then

0.76 V = [8.314 J·K^(-1)mol^(-1) × 298.15 K]/[2 × 96 485 J·V^(-1)mol^(-1)]ln<em>K</em>

0.76 = 0.012 85 ln<em>K</em>

ln<em>K</em> = 0.76/0.012 85 = 59.16

<em>K</em> =e^59.16 = 5.0 × 10^25

4 0

3 years ago

Liquid X is known to have a lower viscosity and lower surface tension than Liquid Y Use these facts to predict the result of eac

Dima020 [189]

Liquid is safe i think hope this helps

8 0

3 years ago

Why do you use the same amount of water for each shape of ice?

Fiesta28 [93]

Answer:

Ice is a solid form of liquid. Water simply expands when it freezes.

The same amount of water for each shape of ice because the melting rate of ice depends on the surface area of each shape. So the same amount of water or volume with a large surface area will remain frozen for longer time.

4 0

3 years ago

if 28.5 g of calcium hydroxide is dissolved in enough water to make 185g of solution what is the percent by mass of calcium hydr

DENIUS [597]

The percent by mass of calcium hydroxide in the solution : 15.41%

<h3>Further explanation</h3>

The concentration of a substance can be expressed in several quantities such as moles, percent (%) weight/volume,), molarity, molality, parts per million (ppm) or mole fraction. The concentration shows the amount of solute in a unit of the amount of solvent.

Mass of solute (Ca(OH₂-Calcium hydroxide) : 28.5

Mass of solution = 185 g

$\tt \%mass=\dfrac{mass~solute}{mass~solution}\times 100\%\\\\\%mass=\dfrac{28.5~g}{185~g}\times 100\%\\\\\%mass=15.41\%$

6 0

3 years ago