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irakobra [83]
3 years ago
8

Perform the following conversion: (plz show work) 1.31km = _______m

Chemistry
1 answer:
PilotLPTM [1.2K]3 years ago
6 0
If this is meters, then it’d be 1310.

1km = 1000m

.31 x 1000 = 310

So, 1000 + 310 = 1310m
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5 0
2 years ago
What is the surface area of the given figure?
eduard

Answer:

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3 0
2 years ago
Which is a factor into Tyrone in the average atomic mass of an element
nikklg [1K]

The mass numbers of the different isotopes of that element are averaged according to their respective abundances in nature.

6 0
3 years ago
3. How many atoms are found in 5.20 g of magnesium (Mg)?
Ganezh [65]

Explanation:

In order to go from mass of magnesium to atoms of magnesium, we have to do two things:

   Convert mass of Mg to moles of Mg using the molar mass of Mg as a conversion factor

   Convert moles of Mg to atoms of Mg using Avogadro's number (6.02×1023) as a conversion factor

Step 1:

Before we start, I should note that the molar mass of Mg is 24.31gmol. We can go from mass to moles using dimensional analysis. The key to dimensional analysis is understanding that the units that you don't need any more cancel out, leaving the units that are desired:

48.60g

×1mol24.31g

=2.00mol

Step 2:

We'll use this relationship:

www.sprinklernewz.uswww.sprinklernewz.us

Using the moles of Mg that we just obtained, we can use Avogrado's number to perform dimensional analysis in order to cancel out units of mol to end up with atoms of Mg:

2.00mol

×6.02×1023atoms1mol

=1.204×1024atoms

Thus, 48.60g of Mg is equivalent to 1.204×1024atoms

Hope this helped :)

6 0
2 years ago
2) If I have an unknown quantity (# of moles) of gas at a pressure of 32 atm, a volume of 70 L, and a temperature of 25˚C. How m
astra-53 [7]

Answer:

91.5 mol

Explanation:

Volume of gas = 70 L

Temperature = 25°C

Pressure = 32 atm

Moles of gas  = ?

Solution:

The given problem will be solve by using general gas equation,

PV = nRT

P= Pressure

V = volume

n = number of moles

R = general gas constant = 0.0821 atm.L/ mol.K  

T = temperature in kelvin

Now we will convert the temperature.

25+273.15 = 298.15 K

By putting values,

32 atm × 70 L = n ×0.0821 atm.L /mol.K × 298.15 K

2240 atm.L = n ×24.48 atm.L /mol

n = 2240 atm.L / 24.48  atm.L /mol  

n = 91.5 mol

3 0
3 years ago
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