All categories

3 years ago

Perform the following conversion: (plz show work) 1.31km = _______m

Chemistry

1 answer:

PilotLPTM [1.2K]3 years ago

6 0

If this is meters, then it’d be 1310.

1km = 1000m

.31 x 1000 = 310

So, 1000 + 310 = 1310m

You might be interested in

A fish tank holds 45 gal of water. How many kilograms of water are in the fish tank?

larisa [96]

Answer:

How to convert 45 gal to kg? You can use the following formula to convert from Gallon to Kilograms :

X(kg) = y(gal) / 0.264172053

To convert 45 Gallon to Kilograms:

X(oz) = 45(gal) / 0.264172053

Answer: 170.3435 kg

7 0

2 years ago

How much heat is released when 75 g of octane is burned completely if the enthalpy of combustion is -5,500 kJ/mol CsH18? C8H18 +

aalyn [17]

Answer : The correct option is, (D) 3600 kJ

Explanation :

Mass of octane = 75 g

Molar mass of octane = 114.23 g/mole

Enthalpy of combustion = -5500 kJ/mol

First we have to calculate the moles of octane.

$\text{ Moles of octane}=\frac{\text{ Mass of octane}}{\text{ Molar mass of octane}}=\frac{75g}{114.23g/mole}=0.656moles$

Now we have to calculate the heat released in the reaction.

As, 1 mole of octane released heat = -5500 kJ

So, 0.656 mole of octane released heat = 0.656 × (-5500 kJ)

= -3608 kJ

≈ -3600 kJ

Therefore, the heat released in the reaction is 3600 kJ

5 0

3 years ago

How many oxygen molecules are required for glycolysis

morpeh [17]

Answer:

Explanation:

glycolysis requires no oxygen

6 0

2 years ago

Read 2 more answers

Calculate the molarity of hydroxide ion in an aqueous solution that has a poh of 5.00

Simora [160]

Answer:

1.00 x 10^-5 M

Explanation:

pOH=-log[OH^-]

[OH^-]=10^(-pOH)

=10^-5

=1.00 x 10^-5 M

4 0

3 years ago

Jason measures three values of density for his unknown. The values he obtains are: 1.019 g/mL 1.498 g/mL 1.572 g/mL What is the

jok3333 [9.3K]

<u>Answer:</u> The average of the densities of the given measurements is 1.363 g/mL

<u>Explanation:</u>

The equation used to calculate density of a substance is given by:

$\text{Density of a substance}=\frac{\text{Mass of a substance}}{\text{Volume of a substance}}$

We are given:

First measured value of density, $d_1$ = 1.019 g/mL

Second measured value of density, $d_2$ = 1.498 g/mL

Third measured value of density, $d_3$ = 1.572 g/mL

Putting values in above equation, we get:

$\rho_{mix}=\frac{d_1+d_2+d_3}{3}$

$\rho=\frac{1.019+1.498+1.572}{3}\\\\\rho=1.363g/mL$

Hence, the average of the densities of the given measurements is 1.363 g/mL

7 0

3 years ago