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const2013 [10]
3 years ago
14

Write a balanced formation equation at standard conditions for the compound HI.

Chemistry
2 answers:
allsm [11]3 years ago
8 0
H₂(g) + I₂(s) = 2HI(g)
Montano1993 [528]3 years ago
6 0
<span>H2 + I2 --> 2HI
hope it helps
</span>
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How many molecules are there in 45.0 grams of CH ?
Sonbull [250]

Answer:

There are 1.8021 ⋅ 1024 molecules of CH4 in 48 grams of CH4. To answer this question, you must understand how to convert grams of a molecule into the number of molecules. To do this, you have to utilize the concepts of moles and molar mass. A mole is just a unit of measurement. Avogadro's number is equal to 6.022 ⋅1023 molecules/mole. i think please dont complain to me if its wrong im sorry

Explanation:

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The molecule shown belongs to which class of compounds
Kaylis [27]
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7 0
3 years ago
What is the mass of 2.65 millimoles of sulfur?
Bas_tet [7]
Divide this problem in to two steps: 1. Convert millimoles to moles. 2. Convert moles to grams.

1.
2.65 mlmol x 1mol/1000mlmol=.00265mol

2.
.00265mol x 32.065g/1 mol=.0850g S

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6 0
3 years ago
Work done after rutherford's gold foil experiment demonstrated that the nucleus contained ________.
shutvik [7]
Protons and neutrons

hope this helps 
5 0
3 years ago
If a student has 125 mL of a 4.00 M CuSO4 solution and needs a 1.50 M solution, what volume do they need to dilute it to?
lara31 [8.8K]

Answer:

333.3mL

Explanation:

Using the formula as follows:

C1V1 = C2V2

Where;

C1 = initial concentration (M)

C2 = final concentration (M)

V1 = initial volume (mL)

V2 = final volume (mL)

According to the information provided in this question,

C1 = 4.00M

C2 = 1.50M

V1 = 125mL

V2 = ?

Using C1V1 = C2V2

4 × 125 = 1.5 × V2

500 = 1.5V2

V2 = 500/1.5

V2 = 333.3mL

Therefore, the CuSO4 solution needs to be diluted to 333.3mL to make 1.50 M solution.

3 0
2 years ago
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