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Fynjy0 [20]
3 years ago
14

If you were to drop a rock from a tall building, assuming that it had not yet hit the ground, and neglecting air resistance, aft

er it has fallen 22 m:
How much time has passed (in s)?
what is the speed at this distance (in m/s)?
Physics
1 answer:
elena-14-01-66 [18.8K]3 years ago
5 0

Since the object is dropped from some height so its initial speed must be zero

acceleration of the object is due to gravity

so we can use kinematics to find the time it will take to drop by x = 22 m

\delta x = v_i * t + \frac{1}{2}at^2

22 = 0 + \frac{1}{2}*9.8*t^2

t = 2.12 s

Now the speed after 2.12 s will be given as

v_f = v_i + at

v_f = 0 + 9.8 * 2.12

v_f = 20.8 m/s

so above is the speed and time

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Help !!!! Estimate the number of breaths taken by a person during 44 years?
Lisa [10]
44 x 12. I got the 12 from the total of 12 months in a year.


44 > 40

x
12 > 10
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The way my teacher taught me how to estimate is look at the neighbor to 44 and 12. The only time 44 can become 50, is when the neighbor is 5 or up. Same thing for 12. Now, multiply 40 and 10.

40 x 10 = 400.

Therefore, your estimate is 400.

The real answer is 520 breaths.
6 0
3 years ago
Coherent light of frequency 6.37×1014 Hz passes through two thin slits and falls on a screen 88.0 cm away. You observe that the
IgorC [24]

Answer:

The distance between the two slits is 40.11 μm.

Explanation:

Given that,

Frequency f= 6.37\times10^{14}\ Hz

Distance of the screen l = 88.0 cm

Position of the third order y =3.10 cm

We need to calculate the wavelength

Using formula of wavelength

\lambda=\dfrac{c}{f}

where, c = speed of light

f = frequency

Put the value into the formula

\lambda=\dfrac{3\times10^{8}}{6.37\times10^{14}}

\lambda=471\ nm

We need to calculate the distance between the two slits

m\times \lambda=d\sin\theta

d =\dfrac{m\times\lambda}{\sin\theta}

Where, m = number of fringe

d = distance between the two slits

Here, \sin\theta =\dfrac{y}{l}

Put the value into the formula

d=\dfrac{3\times471\times10^{-9}\times88.0\times10^{-2}}{3.10\times10^{-2}}

d=40.11\times10^{-6}\ m

d = 40.11\ \mu m

Hence, The distance between the two slits is 40.11 μm.

7 0
3 years ago
Riding in a car, you suddenly put on the brakes. As you experience it inside the car, do Newton's law apply? Do they apply as se
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Answer with Explanation:

Newton's laws are applicable for inertial frames of reference which is a frame which is not accelerating when seen from the observer standing on earth.

For the person as he presses the brakes his frame is a decelerating frame of reference hence he cannot apply the newtons laws of motion as they are in their original form but if he analyses the motion he has to apply a correction known as  pseudo-force on the object he is analyzing. Pseudo Force has no basis in newton's laws but are a correction that needs to be applied if he wishes to analyse the motion from non inertial frame of reference

While as a person standing on earth outside the car since his frame is an inertial frame of reference he can apply newton's laws of motion without any correction.  

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3 years ago
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pentagon [3]

Answer:

Explanation:

Exercise controls weight. Exercise can help prevent excess weight gain or help maintain weight loss. ...

Exercise combats health conditions and diseases. ...

Exercise improves mood. ...

Exercise boosts energy. ...

Exercise promotes better sleep. ...

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6 0
2 years ago
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