Evaluate f (2) = 3(2) for x = -1.<br> f(-1)

Which word best describes the degree of overlap between the two data sets? Low, High, None, Moderate

zlopas [31]

Answer:

In case of data set given with the question, the word that best describes the degree of overlap between the two data sets is low.

Step-by-step explanation:

Overlapping of two data sets means they contain common data or they have common elements in them.

In case of given data set, the elements are represented by 'x'.

If we compare both, the elements at line 30 and 35 overlap.

We conclude that out of 15 elements in each data set, only two of them overlaps. Hence the degree of overlap is low.

6 0

3 years ago

The foot of a ladder is placed 6 feet from a wall if the top of the ladder rests 8 feet up on the wall how long is the ladder?

Vlada [557]

Try to imagine this word problem, there is a wall and a ladder leaning against it, the space from the bottom of the ladder is labeled 6 and the length of the height the ladder reaches on the wall is 8. Imagine this as a right triangle now, where the length of the ladder is the hypotenuse and the length of the legs of the triangle is 6 and 8. Because we know this, we can use the Pythagorean theorem, a^2+b^2=c^2
We then plug in the values and you get 6^2+8^2=c^2
When you simplify, you get 36+64=c^2 which is c^2=100
When you solve for c, you get c=10 which would be the length of the ladder :)

4 0

3 years ago

Read 2 more answers

6th grade math help me please ! :))

polet [3.4K]

Cost of 32 ounces yoghurt = $1.62

Cost of 1 ounce = $1.62/32 = $0.05 (approx)

3 0

3 years ago

A book is 0.33 meters long. How many millimeters long is it?

Phoenix [80]

we know that

$1\ meter=1,000\ millimeters$

so

by proportion

Find how many millimeters are in $0.33$ meters

$\frac{1,000}{1} \frac{mm}{m} =\frac{x}{0.33} \frac{mm}{m} \\ \\x=1,000*0.33 \\ \\ x=330\ mm$

therefore

<u>the answer is</u>

$330\ mm$

7 0

3 years ago

How many complex zeros does the polynomial function have?<br> f(x)=−3x^6−2x^4+5x+6

REY [17]

one way would be to factor

I can't factor it so we will have to use Descartes' Rule of Signs which is helpful for finding how many real roots you have

it goes like this:

for a polynomial with real coefients, consider $f(x)=-3x^6-2x^4+5x+6$ .

after arranging the terms in decending order in terms of degree, count how many times the signs of the coeffients change direction and minus 2 from that number until you get to 1 or 0. that will be the number of even roots the function can have

We have (-, -, +, +). the signs changed 1 times, so it has 1 real positive root

to get the negative roots, we evaluate f(-x) and see how many times the root changes

$f(-x)=-3x^6-2x^4-5x+6$

signs are (-, -, -, +). there was 1 change in sign

so the function has 1 real negative root

a total of 2 real roots

a function of degree $n$ can have at most, $n$ roots

our function is degree 6 so it has 6 roots

if 2 are real, then the others must be complex

6-2=4 so there are 4 complex roots

you can also show that there are only 2 real roots by using a graphing utility to see that there are only 2 real roots

7 0

3 years ago

Evaluate f (2) = 3(2) for x = -1. f(-1)