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Elodia [21]
3 years ago
12

A quarter-circle with a diameter of 4 meters. What is the area?

Mathematics
1 answer:
Zarrin [17]3 years ago
7 0
First, just find the area of the whole circle:

πr²
π(2)²
4<span>π

Now, just multiply by 1/4.

4</span><span>π * 1/4
</span><span>π
</span><span>
Hope this helps!

</span>
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Answer:

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Step-by-step explanation:

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Which of the following are solutions to the equation below? Check all that apply. 9x^2-64=0
nikdorinn [45]

Answer:

E. -8/3

F. 8/3

Step-by-step explanation:

9x^2-64=0

Add 64 to each side

9x^2-64+64 = 0+64

9x^2 =64

Divide each side by 9

9x^2/9 = 64/9

x^2 = 64/9

Take the square root of each side

sqrt(x^2) = ±sqrt(64/9)

We know that sqrt(a/b) = sqrt(a)/sqrt(b)

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10 · c − 8 · 95 = (10 − 8) · 95
Westkost [7]

Answer:

x=95

Step-by-step explanation:

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2 years ago
Binomial theorem Expand (5 - y)3
Snowcat [4.5K]

Answer:

(5 - y) ^3 = 125 - 75y + 15y^2 - y^3

Step-by-step explanation:

Binomial expression

1

1. 1

1. 2. 1

1. 3. 3. 1 --------power of 3

( 5 - y) ^3

( 5 - y) (5 - y) (5 - y)

( a + b) ^3 = a^3 + 3a^2b + 3ab^2 + b^3

a = 5

b = -y

( 5 - y) ^2 = ( 5 - y) (5 - y)

= 5( 5 - y) - y(5 - y)

= 25 - 5y - 5y + y^2

=(25-10y+y^2)

( 25 - 10y + y^2)( 5 - y)

= 5(25 - 10y + y^2) - y( 25 - 10y + y^2)

= 125 - 50y + 5y^2 - 25y + 10y^2 - y^3

Collect the like terms

= 125 - 50y - 25y + 5y^2 + 10y^2 - y^3

= 125 - 75y + 15y^2 - y^3

7 0
3 years ago
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