Always true because addition and subtraction is commutative
-6.2-(-3.96) = -2.24
-3.96-(-6.2)= -2.24
5.71+2.84=8.55
2.84+5.71=8.55
Hope this helped :)
1) it must be fulfilled that the denominator is different from zero, then for this expression
x^2 -9 ⇒ x^2-3^2 = (x-3)(x+3)⇒ (x-3)(x+3) = 0 ⇒ x = 3 o x = -3 , the dominium is all numbers reals except 3 and -3
Answer:
The student ticket is 200 and the adults is 550
Step-by-step explanation:
So the set up is :
750 = x + y
5300 = 8x + 4.5 y
x will be adults and y will be students
Assuming you don't have calculator then you want to be able to eliminate either x or y from this system. The easiest is X cause its a whole number.
So multiply all the numbers from the first equation by 8 which gives
6000 = 8x + 8 y
5300 = 8x + 4.5 y
Then subtract the numbers (6000-5300 and 8x-8x and 8y-4.5y)
which gives :
700 = 3.5y
Solve for y = 200
and plug 200 back into any equation to solve for X
750 = x + 200
x = 550
Answer:
-16
Step-by-step explanation:
b) -x²; x = -4
-(-4)²
-(16)
-16
I hope this helps!
