Answer:
Explanation:
Given parameters:
Molarity of KOH = 0.26M
Volume of H₂SO₄ = 19.76mL
Molarity of H₂SO₄ = 0.20M
Unknown:
Volume of KOH = ?
Solution:
This is a neutralization reaction in which an acid reacts with a base to produce salt and water:
H₂SO₄ + 2KOH → K₂SO₄ + 2H₂O
We solve from the known to the unknown in the reaction.
The known is the acid and from there we can find the number of moles of the acid to be completely neutralized:
Number of moles of acid = molarity x volume
Number of moles of acid = 19.76 x 0.20 = 3.95mol
From the balanced reaction equation:
1 mole of acid reacts with 2 moles of the bases KOH
3.95mole of acid would react with 3.95moles x 2 of the base
Number of moles of reacting base = 7.90moles
To find the volume of base;
Volume of base = 
Volume = 
= 30.40mL
Learn more:
Neutralization brainly.com/question/6447527
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<span>Active transport runs counter to facilitated diffusion. In active transport, molecules move against the concentration gradients, running from areas of lower concentration to areas of higher concentration. This is where energy is used.</span>
Answer:
pH = 2.97
Explanation:
Aspirin, (HC₉H₇O₄), is in equilibrium with water, thus:
HC₉H₇O₄(aq) + H₂O(l) ⇄ C₉H₇O₄⁻(aq) + H₃O⁺(aq)
Ka = 3.0x10⁻⁴ = [C₉H₇O₄⁻][H₃O⁺] / [HC₉H₇O₄]
When you add 0.0050M of aspirine, the solution reach equilibrium when concentrations are:
[HC₉H₇O₄] = 0.0050M - x
[C₉H₇O₄⁻] = x
[H₃O⁺] = x
Replacing in Ka formula:
3.0x10⁻⁴ = [x][x] / [0.0050-x]
1.5x10⁻⁶ - 3.0x10⁻⁴X = X²
X² + 3.0x10⁻⁴X - 1.5x10⁻⁶ = 0
Solving for x:
x = - 0.00138 → False answer. There is no negative concentrations
x = 0.00108 → Right answer
As [H₃O⁺] = x; [H₃O⁺] = 0.00108M.
pH = -log[H₃O⁺]
<em>pH = 2.97</em>
Answer:anions with least precipitates are anions of salt produce by a strong acid and strong base e.g KCL,Na2SO4,
Explanation: salts produce from strong acid such as HCL and a strong base such as KOH are extremely soluble and hence produce little or no precipitate when dissolved in water .meaning the salt are highly soluble , most group1 elements form salts that are highly soluble and hardly precipitates e.g Na(sodium) pottasium(K) ,lithium(Li)salts.they are called alkaline metals.
B) exception to the rules are hydrogen and Rubidium.hydrogen because it occurs basically as a gas and forms H^+ which tend to form a hydrogen bond while rubidium is a heavy metal forming insoluble salt
