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3 years ago

Which of the following processes is involved in the formation of sedimentary rocks?

Chemistry

2 answers:

AlladinOne [14]3 years ago

6 0

D. deposition

hope i can help

riadik2000 [5.3K]3 years ago

4 0

Answer:

deposition

Explanation:

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Which specific gas is most abundant in earth's atmosphere?

elena-14-01-66 [18.8K]

Nitrogen is 78.08% of the air is fills the earth's atmosphere.

8 0

3 years ago

Read 2 more answers

5.68 x 10^4 mL to L Express your answer to three sianificant fiqures and includ

olasank [31]

Answer:

5.68 × 10⁴ mL = 56.8 L

Explanation:

Volume is defined as the amount of three-dimensional closed space. The SI unit of volume is cubic metre which is denoted by the symbol m³.

According to the metric system, other units of volume include: litre (L), millilitre (mL) and cubic centimetre (cm³).

Since, 1 mL = 0.001 L = 10⁻³ L

Therefore, 5.68 × 10⁴ mL = 5.68 × 10⁴ × 10⁻³ L = 5.68 × 10 L = 56.8 L

5.68 × 10⁴ mL = 56.8 L, has three non-zero significant figures.

3 0

4 years ago

A 312 g sample of a metal is heated to 277.845 °C and plunged into 200 g of water at a temperature of 11.945 °C. The final tempe

tigry1 [53]

Answer:

The specific heat capacity of the metal is 1.307 J/g °C

Explanation:

Step 1: Data given

mass of the metal = 312 grams

initial temperature of the metal ( before plunged in the water) = 277.845 °C

initial temperature water = 11.945 °C

Final temperature of water (and aslo the metal) = 99.062 °C

Specific heat capacity of wayer = 4.184 J/g °C

Step 2: Calculate the specifi heat capacity of the metal

Loss of Heat of the Metal = Gain of Heat by the Water

Qmetal = -Qwater

m(metal) * C(metal) * ΔT(metal) = - m(water) * C(water) * ΔT(water)

with mass of metal = 312 grams

with C(metal) = TO BE DETERMINED

with ΔT (metal) = 99.062 - 277.845 = -178.783 °C

with mass of water = 200 grams

with C(water) = 4.184 J/°C * g

with ΔT (water) = 99.062 - 11.945 = 87.117 °C

312 * C(metal) * -178.783 = - 200* 4.184 * 87.117

C(metal) = -72899.51 / 55780.296 = 1.307

The specific heat capacity of the metal is 1.307 J/g °C

6 0

3 years ago

Can can someone lease check my answers and tell me if im right???

zubka84 [21]

Technically, this question is badly worded. If all 4 containers were at STP, then all 4 containers would have the same pressure. So I'll assume instead that all 4 containers are at the same temperature, and then use the ideal gas law to determine the relative internal pressures of each container.

The idea gas law is
PV = nRT
where
P = Pressure
V = Volume
n = number of moles
R = Ideal gas constant
T = Absolute temperature

Since all the containers are at the same temperature, we can ignore the R and T parts of the formula and substitute some value K for constant. So we get PV = nK

Now solve for P
PV = nK
P = nK/V

From the above, you can see that the pressure is proportional to the number of moles divided by the volume. So let's calculate that value for each container.
Container A: 0.5 / 11.2 = 0.044642857
Container B: 2 / 22.4 = 0.089285714
Container C: 1 / 22.4 = 0.044642857
Container D: 2 / 11.2 = 0.178571429
So as you can see, the pressures in containers A and C are the same, which is the first available option, so you are correct.

6 0

4 years ago

Which of the following is NOT useful in

Kipish [7]

The price would not be a physical property

4 0

2 years ago