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iogann1982 [59]
3 years ago
13

A cube 20 cm on one side could contain how many milliliters of fluid

Chemistry
2 answers:
Dmitriy789 [7]3 years ago
4 0
Hello itsbabyrene99!
The answer to your question is 800 cm^3.
.
V = s^3
V = (20cm)^3
V = 800 cm^3
:)
RideAnS [48]3 years ago
3 0

Answer:

A cube 20 cm on one side could contain 8,000 milliliters of fluid.

Explanation:

Edge length of the cube ,a= 20 cm

A volume of the cube = a^3=a\times a\times a

V=20 cm\times 20 cm\times 20 cm=8,000 cm^3

1 cm^3= 1mL

So, the cube of volume 8000 cm^3 will hold 8000 cm^3 of fluid.

8,000 cm^3=8,000 mL

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Water acts as a<br> solvent<br> solute<br> solution<br> mixture
Serhud [2]
Answer: universal Solvent

Explanation: water can dissolve many substances than any other solvent. Because of this, water is sometimes called a UNIVERSAL SOLVENT.
5 0
3 years ago
Group 17 is called the halogen family, and the group to its right is called the noble gases. How are the elements in these group
Firlakuza [10]

Answer: they all have 7  electrons they have different atom sizes

Explanation: hope it helps

7 0
3 years ago
If the solubility of KCl in 100 mL of H₂O is 34 g at 20 °C and 43 g at 50 °C, label each of the following solutions as unsaturat
sertanlavr [38]

Answer:

a) Unsaturated

b) Supersaturated

c) Unsaturated

Explanation:

A saturated  solution contains the <u>maximum amount of a solute that will dissolve in a given  solvent at a specific temperature</u>.

An unsaturated solution contains <u>less solute than it  has the capacity to dissolve. </u>

A supersaturated solution, <u>contains more  solute than is present in a saturated solution</u>. Supersaturated solutions are not very  stable. In time, some of the solute will come out of a supersaturated solution as crystals.

According to these definitions and considering that the solubility of KCl in 100 mL of H₂O at <u>20 °C is 34 g</u>, and at <u>50 °C is 43 g</u> we can label the solutions:

a) 30 g in 100 mL of H₂O at 20 °C  ⇒ unsaturated

b) 65 g in 100 mL of H₂O at 50 °C  ⇒ supersaturated

c) 42 g in 100 mL of H₂O at 50 °C and slowly cooling to 20 °C to give a clear solution <u>with no precipitate</u> ⇒ unsaturated (if it were saturated it would have had precipitate)

8 0
3 years ago
Why is the answer C for this problem?
pshichka [43]

Answer:

\boxed{\text{(C) X}$_{3}$P$_{2}}

Explanation:

Step 1. Identify the Group that contains X

We look at the consecutive ionization energies and hunt for a big jump between them

\begin{array}{crc}n & IE_{n} & IE_{n} - IE_{n-1}\\1 & 730 & \\2 & 1450 & 720\\3 & 7700 & 6250\\4 & 10500 & 2800\\\end{array}

We see a big jump between n = 2 and n = 3. This indicates that X has two valence electrons.

We can easily remove two electrons, but the third electron requires much more energy. That electron must be in the stable, filled, inner core.

So, X is in Group 2 and P is in Group 15.

Step 2. Identify the Compound

X can lose two valence electrons to reach a stable octet, and P can do the same by gaining three electrons.

We must have 3 X atoms for every 2 P atoms.

The formula of the compound is \boxed{\text{X}$_{3}$P$_{2}}$}.

4 0
3 years ago
We do we mean when we say a substance is pure
tiny-mole [99]

Answer:

ot means that contains only one kind of matter. 

6 0
3 years ago
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