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3 years ago

A cube 20 cm on one side could contain how many milliliters of fluid

Chemistry

2 answers:

Dmitriy789 [7]3 years ago

4 0

Hello itsbabyrene99!
The answer to your question is 800 cm^3.
.
V = s^3
V = (20cm)^3
V = 800 cm^3
:)

RideAnS [48]3 years ago

3 0

Answer:

A cube 20 cm on one side could contain 8,000 milliliters of fluid.

Explanation:

Edge length of the cube ,a= 20 cm

A volume of the cube = $a^3=a\times a\times a$

$V=20 cm\times 20 cm\times 20 cm=8,000 cm^3$

$1 cm^3= 1mL$

So, the cube of volume $8000 cm^3$ will hold $8000 cm^3$ of fluid.

$8,000 cm^3=8,000 mL$

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If you had 100 ml of juice, how many milliliter would de fruit juice?

Julli [10]

Since the measurement is not changing, the answer is 100 mL. Hope this helps.

8 0

3 years ago

Consider the following reaction at a high temperature. Br2(g) ⇆ 2Br(g) When 1.35 moles of Br2 are put in a 0.780−L flask, 3.60 p

UNO [17]

Answer : The equilibrium constant $K_c$ for the reaction is, 0.1133

Explanation :

First we have to calculate the concentration of $Br_2$ .

$\text{Concentration of }Br_2=\frac{\text{Moles of }Br_2}{\text{Volume of solution}}$

$\text{Concentration of }Br_2=\frac{1.35moles}{0.780L}=1.731M$

Now we have to calculate the dissociated concentration of $Br_2$ .

The balanced equilibrium reaction is,

$Br_2(g)\rightleftharpoons 2Br(aq)$

Initial conc. 1.731 M 0

At eqm. conc. (1.731-x) (2x) M

As we are given,

The percent of dissociation of $Br_2$ = $\alpha$ = 1.2 %

So, the dissociate concentration of $Br_2$ = $C\alpha=1.731M\times \frac{1.2}{100}=0.2077M$

The value of x = 0.2077 M

Now we have to calculate the concentration of $Br_2\text{ and }Br$ at equilibrium.

Concentration of $Br_2$ = 1.731 - x = 1.731 - 0.2077 = 1.5233 M

Concentration of $Br$ = 2x = 2 × 0.2077 = 0.4154 M

Now we have to calculate the equilibrium constant for the reaction.

The expression of equilibrium constant for the reaction will be :

$K_c=\frac{[Br]^2}{[Br_2]}$

Now put all the values in this expression, we get :

$K_c=\frac{(0.4154)^2}{1.5233}=0.1133$

Therefore, the equilibrium constant $K_c$ for the reaction is, 0.1133

7 0

3 years ago

One radioactive isotope of calcium has an atomic mass of 47,how many neutrons are in the calcium -47 nucleus

jekas [21]

Answer: 27 neutrons

Explanation:

Recall that the number of protons in the nucleus of an atom = Atomic number.

Hence, Calcium with mass number 47 and atomic number 20 will have 20 protons

Therefore, since Mass number = number of protons + neutrons

47 = 20 + neutrons

Neutrons = 47 - 20 = 27

Thus, there are 27 neutrons in radioactive calcium nucleus.

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3 years ago

What did J. J. Thomson observe when he applied electric voltage to a cathode ray tube in his famous experiment?

Nataly_w [17]

The glass opposite to the negative electrode started to glow. Hence, option B is correct.

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J.J. Thomson, through his famous Cathode ray experiment, proved that all atoms contain small negatively charged particles known as electrons. In the experiment, he applied electric voltage across a cathode ray tube. a fluorescent material coating was done on the positive side. When the voltage was applied, the positive side has glowing dots.

Hence, option B is correct.

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1 year ago

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tino4ka555 [31]

Answer:

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Explanation:

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