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lions [1.4K]
4 years ago
6

Are routers better for internet connection rather than a WiFi modem?

Engineering
2 answers:
sleet_krkn [62]4 years ago
8 0

Answer:

Depends

Explanation:

The modem connects you to the Internet via ISP. Without a modem, your router will only allow you to connect to a LAN. A modem will provide connections for just a single wired device. If you want to go wireless you need a router.

bulgar [2K]4 years ago
5 0

Answer:

I don't exactly know the answer, but i found a  helpful website that could help you.

www.tomsguide.com

just copy and paste it.

search up modem vs router.

Explanation:

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Almost all collisions are due to driver error
blondinia [14]

Answer:

Where's the questaion?

4 0
2 years ago
Two different fuels are being considered for a 2.5 MW (net output) heat engine which can operate between the highest temperature
sveta [45]

Answer:

If the heat engine operates for one hour:

a) the fuel cost at Carnot efficiency for fuel 1 is $409.09 while fuel 2 is $421.88.

b) the fuel cost at 40% of Carnot efficiency for fuel 1 is $1022.73 while fuel 2 is $1054.68.

In both cases the total cost of using fuel 1 is minor, therefore it is recommended to use this fuel over fuel 2. The final observation is that fuel 1 is cheaper.

Explanation:

The Carnot efficiency is obtained as:

\epsilon_{car}=1-\frac{T_c}{T_H}

Where T_c is the atmospheric temperature and T_H is the maximum burn temperature.

For the case (B), the efficiency we will use is:

\epsilon_{b}=0.4\epsilon_{car}

The work done by the engine can be calculated as:

W=\epsilon Q=\epsilon H_v\cdot m_{fuel} where Hv is the heat value.

If the average net power of the engine is work over time, considering a net power of 2.5MW for 1 hour (3600s), we can calculate the mass of fuel used in each case.

m=\frac{P\cdot t}{\epsilon H_v}

If we want to calculate the total fuel cost, we only have to multiply the fuel mass with the cost per kilogram.

TC=m\cdot c

8 0
3 years ago
________ delivers the precise number of parts to be assembled into a finished product at precisely the right time.
Roman55 [17]

Answer:

JIT

Explanation:

JIT stands for just-in-time

6 0
2 years ago
Problem 2 (a) A sinusoid with a frequency of 2Hz is applied to a sampler/zero-order hold combination. The sampling rate is 10Hz.
madreJ [45]

Answer & Explanation:

(a) Frequency of 2Hz is applied to a sampler/zero-order hold combination

The sampling rate is 10Hz

List of all the frequencies present in the output that are less than 50Hz.

Adding:

fs + fm = 10 + 2

= 12 Hz

2fs + fm = 2 * 10 + 2

= 22 Hz

3fs + fm = 3 * 10 + 2

= 32 Hz

4fs + fm = 4 * 10 + 2

= 42 Hz

Subtracting:

fs - fm = 10 - 2

= 8 Hz

2fs - fm = 2 * 10 - 2

= 18 Hz

3fs - fm = 3 * 10 - 2

= 28 Hz

4fs - fm = 4 * 10 - 2

= 38 Hz

5fs - fm = 5 * 10 - 2

= 48 Hz

(b) Frequency of 8Hz is applied to a sampler/zero-order hold combination

The sampling rate is 10Hz

List of all the frequencies present in the output that are less than 50Hz.

Adding:

fs + fm = 10 + 8

= 18 Hz

2fs + fm = 2 * 10 + 8

= 28 Hz

3fs + fm = 3 * 10 + 8

= 38 Hz

Subtracting:

fs - fm = 10 - 8

= 2 Hz

2fs - fm = 2 * 10 - 8

= 12 Hz

3fs - fm = 3 * 10 - 8

= 22 Hz

4fs - fm = 4 * 10 - 8

= 32 Hz

5fs - fm = 5 * 10 - 8

= 42 Hz

3 0
3 years ago
Question 29: Returns a string based on input string The function below takes a single string parameter: input_string. If the inp
kirill [66]

Answer:

Two Python codes are explained for the problem. Modify as appropriate

Explanation:

<u>CODE 1:</u>

def string_contains(input_string): # called function

if(input_string.__contains__('z')): # Check input_string contains 'z'

print('has the letter z.') # print input_string contains 'z'

else:

print('not worthwhile.') # print if input_string not contains 'z'

input_string = input('Please enter the string: ') # ACeept string from user

string_contains(input_string) # calling function where we pass input_string as actual parameter

<u>CODE 2:</u>

def string_contains(input_string):

   for x in input_string:

       if x=='z':

           return 'has the letter z'

   return 'not worthwhile'

8 0
3 years ago
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