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suter [353]
3 years ago
9

(3) In the following power system, the transformer is assumed to be ideal. Determine the: a) currents and voltages across each i

mpedance (source impedance, transmission impedance, and load impedance). b) power supplied by the source (average, apparent, and reactive). c) power factor of the source.

Engineering
1 answer:
Anuta_ua [19.1K]3 years ago
6 0

Answer:

Explanation:

Solved solution is in the attached document.

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To convert a whole number to a fraction the number can be written over a denominator of
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When you convert a whole number into a fraction, you put the whole number as the numerator and the denominator as 1.

Such as 12=12/1 or 5=5/1
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The high-pressure fuel pumps used in gasoline direct-injection (GDI) systems are powered by ________.
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A fluid flows along the x axis with a velocity given by V = (xt) i ˆ, where x is in feet and t in seconds. (a) Plot the speed fo
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See explanation for step by step procedures towards getting answers

Explanation:

Given that;

A fluid flows along the x axis with a velocity given by V = (xt) i ˆ, where x is in feet and t in seconds. (a) Plot the speed for 0 ≤ x ≤ 10 ft and t = 3 s. (b) Plot the speed for x = 7 ft and 2 ≤ t ≤ 4 s. (c) Determine the local and convective acceleration. (d) Show that the acceleration of any fluid particle in the flow is zero. (e) Explain physically how the velocity of a particle in this unsteady flow remains constant throughout its motion.

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3 years ago
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When leveraging Artificial Intelligence (AI) in today's business landscape, which statement represents the data leveraged for so
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The transfer function of a linear system is defined as the ratio of the Laplace transform of the output function y(t) over the r
faltersainse [42]

Answer:

H(s) = Y(s)/G(s) = 1/(s² + 8s + 6)

Explanation:

Since we are required to determine the transfer function G(s) and Y(s) = G(s)H(s). So, H(s) = Y(s)/G(s).

Since our system is given as y′′(t) + 8y′(t) +6y(t) = g(t), t>0 with all initial condition zero, that is, y(0) = 0, y"(0) = 0 and g(0) = 0.

Taking the Laplace transform of both the left hand side and right hand side of the equation, we have

y′′(t) + 8y′(t) +6y(t) = g(t),

L{y′′(t) + 8y′(t) +6y(t)} = L{g(t)}

L{y′′(t)} + L{8y′(t)} + L{6y(t)} = L{g(t)}

L{y′′(t)} + 8L{y′(t)} + 6L{y(t)} = L{g(t)}

[s²Y(s) - sy(0) - y'(0)] + 8[sY(s) - y(0)] + 6Y(s) = G(s)

[s²Y(s) - s(0) - 0] + 8[sY(s) - 0] + 6Y(s) = G(s)

s²Y(s) + 8sY(s) + 6Y(s) = G(s)

(s² + 8s + 6)Y(s) = G(s)

Y(s)/G(s) = 1/(s² + 8s + 6)

So, H(s) = Y(s)/G(s) = 1/(s² + 8s + 6)

6 0
3 years ago
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