Answer:
- x = 0 or 1
- x = ±i/4
- x = -5 (twice)
Step-by-step explanation:
Factoring is aided by having the equations in standard form. The first step in each case is to put the equations in that form. The zero product property tells you that a product is zero when a factor is zero. The solutions are the values of x that make the factors zero.
1. x^2 -x = 0
x(x -1) = 0 . . . . . x = 0 or 1
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2. 16x^2 +1 = 0
This is the "difference of squares" ...
(4x)^2 - (i)^2 = 0
(4x -i)(4x +i) = 0 . . . . . x = -i/4 or i/4 (zeros are complex)
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3. x^2 +10x +25 = 0
(x +5)(x +5) = 0 . . . . . x = -5 with multiplicity 2
Answer:
f(x) = -2x+5
f(x+h) = -2x -2h +5
g(x) = -4x-2
g(x+h) = -4x -4h -2
h(x) = 4x^2+1
h(x+h) = 4(x+h)^2 +1 = 4x^2 +8xh + 4h^2 +1
Q(x) = -3x^2 +4
Q(x+h) = -3(x+h)^2 +4 = -3x^2 -3h^2 -6xh + 4
- Midpoint Formula:
So firstly, let's start with the x-coordinates. Since we know the midpoint's x-coordinate and point A's x-coordinate, we can solve for point B's x-coordinate as such:
Next, do the same thing except solve for the y-coordinate and using point A's y-coordinate and the midpoint's y-coordinate:
<u>Putting it together, point B's coordinates are (2,4).</u>
Answer:
A. Reflect across the y-axis
Step-by-step explanation:
if the negative sign was outside the radical then it would've been a reflection on the x-axis.
