Answer:
Ksp = 0.1762
Explanation:
Applying
a) moles of HCl added, n= CV=0.5×0.012 = 6×10-3mol
b) since 0.006mol is present in 0.012dm3 of HCl
It implies moles of borax
C) Concentration = 0.706M
Ksp = [0.5]^2[0.706]= 0.176
Answer:
613 mg
Explanation:
Number of fargday's 
Here, I = 9.20 A
t = 10.5 min
= 10.5 x 60 seconds
So, 
= 0.0208 F
Here, 2e, 2F
2F = 1 mol of Ni
1 mol = 59 gm of Ni
0.0104 mol = 59 x0.0104 gm Ni
= 0.613 gm Ni
= (0.613 x 1000 ) mg of Ni
= 613 mg of Ni
Answer:
7.03 g
Explanation:
Step 1: Write the balanced synthesis reaction
N₂(g) + 3 H₂(g) ⇒ 2 NH₃(g)
Step 2: Calculate the moles corresponding to 32.5 g of N₂
The molar mass of N₂ is 28.01 g/mol.
32.5 g × 1 mol/28.01 g = 1.16 mol
Step 3: Calculate the number of moles of H₂ needed to react with 1.16 moles of N₂
The molar ratio of N₂ to H₂ is 1:3. The moles of H₂ needed are 3/1 × 1.16 mol = 3.48 mol.
Step 4: Calculate the mass corresponding to 3.48 moles of H₂
The molar mass of H₂ is 2.02 g/mol.
3.48 mol × 2.02 g/mol = 7.03 g
Answer: Insufficient amount of work provided.
Explanation:
Answer:
true
Explanation:
osmosis is a special case of diffusion. diffusion occurs across a semipermeable membrane and only the water or other solvent moves. Diffusion and osmosis are both passive transport processes that act to equalize the concentration of a solution.
