Answer:
chemical
Explanation:
The chemical properties determine the identity of a substance and are not changed when there is no reaction. In the solution, what takes place is a physical change, which is a change of state (for example, going from solid to aqueous form).
Answer:
Explanation:
Any densities less than 1g/cm3 will float, while objects with densities over 1g/cm3 will sink.
Compounding Corner on RxNet is the best reference for more information regarding compounding
<u>Explanation:</u>
RxNet is an open online community, consolidating scientists from the domains of chemistry, biochemistry and expanding industry of drug innovation and improvement. Compounding presents an innovative way for pharmacists to customize prescriptions to suit the requirements of their patients.
The art of compounding employs advanced medicine while still sticking to the roots of the profession of pharmacy. Compounding pharmacies can create unparalleled dosage forms based on patient preferences. Compounded medicines are usually reliable and sufficient for most victims who have spoken to their physician about their wellness.
D is just straight up false, if I were to take a stab at it, the only one that’s seems logical to me B. “The ability of atoms to combine in unlimited ways”
Answer:
3.74g of ethylene glycol must be added to decrease the freezing point by 0.400°C
Explanation:
One colligative property is the freezing point depression due the addition of a solute. The equation is:
ΔT=Kf*m*i
<em>Where ΔT is change in temperature = 0.400°C</em>
<em>Kf is freezing point constant of the solvent = 1.86°C/m</em>
<em>m is molality of the solution (Moles of solute / kg of solvent)</em>
<em>And i is Van't Hoff constant (1 for a nonelectrolyte)</em>
Replacing:
0.400°C =1.86°C/m*m*1
0.400°C / 1.86°C/m*1 = 0.215m
As mass of solvent is 280.0g = 0.2800kg, the moles of the solute are:
0.2800kg * (0.215moles / 1kg) = 0.0602 moles of solute must be added.
The mass of ethylene glycol must be added is:
0.0602 moles * (62.10g / mol) =
3.74g of ethylene glycol must be added to decrease the freezing point by 0.400°C
<em />