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DIA [1.3K]
3 years ago
12

Name the gas liberated when ethanol react with sodium metal?

Chemistry
1 answer:
expeople1 [14]3 years ago
4 0
<span>When sodium reacts with ethanol, hydrogen gas liberates and leaves a colorless solution of Alkoxide 

Reaction: 2CH</span>₃CH₂OH + 2Na → 2CH₃CH₂ONa + H₂

So, in short the answer of your particular question will be "Hydrogen Gas"

Hope this helps!!!
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A CaCl2 solution is given to increase blood levels of calcium. If a patient receives 6.1 mL of a 12 % (m/v) CaCl2 solution, how
Yuliya22 [10]

Mass of CaCl₂ = 0.732 g

<h3>Further explanation</h3>

The concentration of a substance can be expressed in several quantities such as moles, percent (%) weight / volume,), molarity, molality, parts per million (ppm) or mole fraction. The concentration shows the amount of solute in a unit of the amount of solvent.

\tt \%(m/v)\rightarrow 12\%=\dfrac{mass~CaCl_2}{volume~of~solution}\times 100\%\\\\mass~CaCl_2=12\%\times 6.1\div 100\%\\\\mass~CaCl_2=0.732~g

5 0
3 years ago
The observed brightness of a star depends on which factors?
dimulka [17.4K]

Answer:

b..............

Explanation:

......

6 0
3 years ago
What element is most likely to form a diatomic molecule?
Harman [31]
Bromine (Br) is the only element listed that is a diatomic element. I believe that Bromine is going to be your answer.
5 0
4 years ago
Read 2 more answers
Can anyone help me on this please.
exis [7]
It would have to be 40.0 only because it wouldn’t add up
8 0
2 years ago
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A chemist adds 215.0mL of a 6.0x10^−5/mmolL mercury(II) iodide HgI2 solution to a reaction flask. Calculate the micromoles of me
Snezhnost [94]

The micromoles of mercury(II) iodide : 0.013 μ moles

<h3>Further explanation</h3>

Given

215.0mL of a 6.0x10⁻⁵mmol/L HgI₂

Required

micromoles of HgI₂

Solution

Molarity(M) = moles of solute per liters of solution

Can be formulated :

M = n : V

n = moles

V = volume of solution

V = 215 mL = 0.215 L

so moles of solution :

n = M x V

n = 6.10 mmol/L x 0.215 L

n = 1.312 . 10⁻⁵ mmol

mmol = 10³ micromol

so 1.312 mmol = 1.312.10⁻⁵ x 10³ = 0.01312 micromoles ⇒ 2 sif fig = 0.013 μ moles

6 0
3 years ago
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