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Alecsey [184]
2 years ago
9

2. A vine called the mile-a-minute weed is known for growing at a very fast rate. It can grow up to 0.5 ft per day. How fast in

inches per hour can the mile-a-minute weed grow up to? SHOW YOUR WORK USING CORRECT CONVERSION FACTORS.
Answer:
Mathematics
2 answers:
gayaneshka [121]2 years ago
8 0

Answer:

.25 inches per hour

Step-by-step explanation:

.5 ft

-----------

day

We need to get to inches

1 ft = 12 inches

.5 ft          12 inches      

----------- * ------------

day             1 ft  

We also need to convert days to minutes

1 day = 24 hours

.5 ft           12 inches             1 day          

----------- * ------------   * -------------    

day             1 ft       24 hours      

6 inches

-------------

24 hours

.25 inches per hour

aniked [119]2 years ago
7 0

Answer:

hi

Step-by-step explanation:

hi

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Mr and mrs Lim took their 2 children to the bird park.An adult ticket cost 4 times as much as a child’s ticket.Mr Lim paid a tot
Vinil7 [7]

c = unknown

a = 4c

120 = 2a + 2c

120 = 2(4c) + 2c

120 = 8c + 2c

120 = 10c

120/10 = 10c/10

c = 12

6 0
4 years ago
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Mr. Williams is driving on a highway at an average speed of 50 miles per hour. His destination is 100 miles away. The
svetlana [45]

Answer:

t = -d/50 + 2

0.5 hour

Step-by-step explanation:

Given the equation:

d = 50 - 100t

The inverse function:

A.) solving for t

d = 100 - 50t

d - 100 = - 50t

Divide both sides by - 50

d/-50 - (100/-50) = - 50t/-50

-d/50 - (-2) = t

t = -d/50 + 2

B) using the inverse function:

t = -d/50 + 2

Miles driven (d) = 75, find time (t)

t = - 75/50 + 2

t = - 1.5 + 2

t = 0.5

t is in hours, therefore time left to travel is 0.5 hours or 30 minutes

4 0
3 years ago
A circular railroad-crossing sign has a diameter of 30 inches.
Angelina_Jolie [31]

Diameter = 30

30/2 = 15 15 is the radius

To find area:

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706.5 is the answer

6 0
2 years ago
Choose the answer that shows 5^-15 rewrite using a positive exponent? ​
Mashcka [7]

Answer:

1/5^15

Step-by-step explanation:

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7 0
3 years ago
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Find the 2th term of the expansion of (a-b)^4.​
vladimir1956 [14]

The second term of the expansion is -4a^3b.

Solution:

Given expression:

(a-b)^4

To find the second term of the expansion.

(a-b)^4

Using Binomial theorem,

(a+b)^{n}=\sum_{i=0}^{n}\left(\begin{array}{l}n \\i\end{array}\right) a^{(n-i)} b^{i}

Here, a = a and b = –b

$(a-b)^4=\sum_{i=0}^{4}\left(\begin{array}{l}4 \\i\end{array}\right) a^{(4-i)}(-b)^{i}

Substitute i = 0, we get

$\frac{4 !}{0 !(4-0) !} a^{4}(-b)^{0}=1 \cdot \frac{4 !}{0 !(4-0) !} a^{4}=a^4

Substitute i = 1, we get

$\frac{4 !}{1 !(4-1) !} a^{3}(-b)^{1}=\frac{4 !}{3!} a^{3}(-b)=-4 a^{3} b

Substitute i = 2, we get

$\frac{4 !}{2 !(4-2) !} a^{2}(-b)^{2}=\frac{12}{2 !} a^{2}(-b)^{2}=6 a^{2} b^{2}

Substitute i = 3, we get

$\frac{4 !}{3 !(4-3) !} a^{1}(-b)^{3}=\frac{4}{1 !} a(-b)^{3}=-4 a b^{3}

Substitute i = 4, we get

$\frac{4 !}{4 !(4-4) !} a^{0}(-b)^{4}=1 \cdot \frac{(-b)^{4}}{(4-4) !}=b^{4}

Therefore,

$(a-b)^4=\sum_{i=0}^{4}\left(\begin{array}{l}4 \\i\end{array}\right) a^{(4-i)}(-b)^{i}

=\frac{4 !}{0 !(4-0) !} a^{4}(-b)^{0}+\frac{4 !}{1 !(4-1) !} a^{3}(-b)^{1}+\frac{4 !}{2 !(4-2) !} a^{2}(-b)^{2}+\frac{4 !}{3 !(4-3) !} a^{1}(-b)^{3}+\frac{4 !}{4 !(4-4) !} a^{0}(-b)^{4}=a^{4}-4 a^{3} b+6 a^{2} b^{2}-4 a b^{3}+b^{4}

Hence the second term of the expansion is -4a^3b.

3 0
3 years ago
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