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Zielflug [23.3K]

3 years ago

6

Nicole is playing a video game where each round lasts \dfrac{7}{12} 12 7 start fraction, 7, divided by, 12, end fraction of an

hour. She has scheduled 3\dfrac343 4 3 3, start fraction, 3, divided by, 4, end fraction hours to play the game.

1 answer:

charle [14.2K]3 years ago

7 0

Answer:

45/7 rounds

6 3/7 rounds

Step-by-step explanation:

Here is the full question

Nicole is playing a video game where each round lasts 7/12 fraction of an hour. She has scheduled 3 3/4 fraction hours to play the game. How many rounds can Nicole play? rounds

Number of rounds she can play = total time she has scheduled / length of each round

length of each round = 7/12

total time she has scheduled = 3 3/4

3 3/4 ÷ 7/12

3 3/4 x 12/7

convert to the total time scheduled to an improper fraction

to convert to improper fraction, take the following steps :

Multiply the whole number (3) by the denominator (4) = 3x 4 = 12
Add the numerator to the answer gotten in the previous step = 14 + 3 = 15
divide the number gotten in the previous step by the denominator = 15/4

$\frac{15}{4}$ × $\frac{12}{7}$ = $\frac{45}{7}$ rounds or $6\frac{3}{7}$ rounds

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Professor Halen teaches a College Mathematics class. The scores on the midterm exam are normally distributed with a mean of 72.3

lbvjy [14]

Answer:

14.63% probability that a student scores between 82 and 90

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 72.3, \sigma = 8.9$

What is the probability that a student scores between 82 and 90?

This is the pvalue of Z when X = 90 subtracted by the pvalue of Z when X = 82. So

X = 90

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{90 - 73.9}{8.9}$

$Z = 1.81$

$Z = 1.81$ has a pvalue of 0.9649

X = 82

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{82 - 73.9}{8.9}$

$Z = 0.91$

$Z = 0.91$ has a pvalue of 0.8186

0.9649 - 0.8186 = 0.1463

14.63% probability that a student scores between 82 and 90

3 0

3 years ago

Carlos Martin received a statement from his bank showing a balance of $56.75 as of March 15th his check book shows a balance of

kakasveta [241]

Answer:

$48.87

Step-by-step explanation:

Let the deposited amount between the March 15th and the March 20th be x

Balance on 15th march = $56.75

The bank returned all the cancelled checks but too. One check was for $5 and the other was for $13.25

And he also deposited x amount

After deposits and deductions

So, balance = 56.75 +x - (13.25+5)

The new balance on 20th march = $87.37

⇒ $56.75 +x - (13.25+5)=87.37$

⇒ $56.75 +x - 18.25=87.37$

⇒ $38.5 +x =87.37$

⇒ $x =87.37-38.5$

⇒ $x =48.87$

Hence Carlos deposited $48.87 in his account between the March 15th and the March 20th.

6 0

3 years ago

Read 2 more answers

there are 5 billiard balls in a velvet bag. three of the balls are striped and the other 2 are solid what's the probability of p

katrin [286]

$|\Omega|=5\\ |A|=3\\\\ P(A)=\dfrac{3}{5}$

4 0

3 years ago

4x-y=10 and y=2x-2 answers

Brums [2.3K]

4x - y = 10, y = 2x - 2

4x - (2x -2) = 10

4x - 2x + 2 = 10

2x = 8

x = 4

4(4) - y = 10

-y = -6

y = 6

So x = 4 y= 6

Hope this helps!
Brainliest and a like is much appreciated!

6 0

2 years ago

Read 2 more answers

A researcher reports survey results by stating that the standard error of the mean is 25 the population standard deviation is 40

bezimeni [28]

Answer:

a) A sample of 256 was used in this survey.

b) 45.14% probability that the point estimate was within ±15 of the population mean

Step-by-step explanation:

This question is solved using the normal probability distribution and the central limit theorem.

Normal probability distribution

When the distribution is normal, we use the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

a. How large was the sample used in this survey?

We have that $s = 25, \sigma = 400$ . We want to find n, so:

$s = \frac{\sigma}{\sqrt{n}}$

$25 = \frac{400}{\sqrt{n}}$

$25\sqrt{n} = 400$

$\sqrt{n} = \frac{400}{25}$

$\sqrt{n} = 16$

$(\sqrt{n})^2 = 16^2[tex][tex]n = 256$

A sample of 256 was used in this survey.

b. What is the probability that the point estimate was within ±15 of the population mean?

15 is the bounds with want, 25 is the standard error. So

Z = 15/25 = 0.6 has a pvalue of 0.7257

Z = -15/25 = -0.6 has a pvalue of 0.2743

0.7257 - 0.2743 = 0.4514

45.14% probability that the point estimate was within ±15 of the population mean

3 0

3 years ago