Answer:
B
Explanation:
Resolve the 75N force into 2 components; horizontal and vertical. And remember that there is no acceleration in the downward direction, so apply Newton's second law and equate it to 0.
Answer:
first order date and most recent order date
Explanation:
it was switched. column 5 should be most recent order date because it's 2020 while column 6 should be first order date because it was in 2019
A) The mass is an intrinsic property of an object: it means it depends only on the properties of the object, so it does not depend on the location of the object. Therefore, Gary's mass at 300 km above Earth's surface is equal to his mass at the Earth's surface.
b) The weight of an object is given by

where
m is the mass

is the gravitational acceleration at the location of the object, with G being the gravitational constant, M the mass of the planet and r the distance of the object from the center of the planet.
At the Earth's surface,

, so Gary's weight is

(1)
where m is Gary's mass.
Then, we must calculate the value of g at 300 km above Earth's surface. the Earth's radius is

So the distance of Gary from the Earth's center is

The Earth's mass is

, so the gravitational acceleration is

Therefore, Gary's weight at 300 km above Earth's surface is

(2)
If we compare (1) and (2), we find that Gary's weight has changed by

So, Gary's weight at 300 km above Earth's surface is 91% of his weight at the surface.
Answer:
The magnitude of a uniform electric field that will stop these protons in a distance of 2 m is 1.01 x
N/C
Explanation:
given information,
kinetic energy, KE = 3.25 x
J
proton's mass, m = 1.673 x
kg
charge, q = 1.602 x
C
distance, d = 2 m
to find the electric field that will stop the proton, we can use the following equation:
E = F/q
= (KE/d) / q , KE = Fd --> F = KE/d
= KE/qd
= (3.25 x
J) / (1.602 x
C)(2 m)
= 1.01 x
N/C