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stealth61 [152]
3 years ago
12

What is tangential velocity

Physics
2 answers:
frozen [14]3 years ago
3 0

Answer:

Tangential velocity is the linear speed of any object moving along a circular path

Explanation:

nalin [4]3 years ago
3 0

Answer:

Tangential velocity is the linear speed of any object moving along a circular path. A point on the outside edge of a turntable moves a greater distance in one complete rotation than a point near to the center.

Explanation:

i hope this helps and can i get brainliest pls?

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Heat in the amount of 100 kJ is transferred directly from a hot reservoir at 1320 K to a cold reservoir at 600 K. Calculate the
Zinaida [17]

Answer:0.0909 kJ/K

Explanation:

Given

Temperature of hot Reservoir T_h=1320 K

Temperature of cold Reservoir T_l=600 K

Heat of 100 kJ is transferred form hot reservoir to cold reservoir

Hot Reservoir is Rejecting heat therefore Q_1=-100 kJ

Heat is added to Reservoir therefore Q_2=100 kJ

Entropy change for system

\Delta s=\frac{Q_1}{T_1}+\frac{Q_2}{T_2}

\Delta s=\frac{-100}{1320}+\frac{100}{600}

\Delta s=-0.0757+0.1666=0.0909 kJ/K

As entropy change is Positive therefore entropy Principle is satisfied

         

4 0
3 years ago
Angela has been feeling fatigued. A test to check the basal metabolic rate revealed that she has a low metabolic rate. What is A
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8 0
3 years ago
The behavior of which objects are better explained by Einstein’s general theory of relativity than Newton’s universal law of gra
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7 0
3 years ago
Read 2 more answers
Can somone pls help me??!! i’m very stuck
Alchen [17]

Answer:

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Explanation:

3 0
3 years ago
А A pool of water of refractive index
babymother [125]

Answer:

Apparent depth = 45 cm

Explanation:

The refractive index of water in a pool, n = 4/3

Real depth, d = 60 cm

We need to find its apparent  depth when viewed vertically through  air.​ The ratio of real depth to the apparent depth is equal to the refractive index of the material. Let the apparent depth is d'. So,

n=\dfrac{d}{d'}\\\\d'=\dfrac{d}{n}\\\\d'=\dfrac{60}{\dfrac{4}{3}}\\\\d'=45\ cm

So, the apparent depth is 45 cm.

3 0
3 years ago
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