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stealth61 [152]
3 years ago
12

What is tangential velocity

Physics
2 answers:
frozen [14]3 years ago
3 0

Answer:

Tangential velocity is the linear speed of any object moving along a circular path

Explanation:

nalin [4]3 years ago
3 0

Answer:

Tangential velocity is the linear speed of any object moving along a circular path. A point on the outside edge of a turntable moves a greater distance in one complete rotation than a point near to the center.

Explanation:

i hope this helps and can i get brainliest pls?

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A projectile fired from a gun has initial horizontal and vertical components of velocity equal to 30 m/s and 40 m/s, respectivel
faust18 [17]

Answer:

The time is 5.10 sec.

Explanation:

Given that,

Component of velocity are 30 m/s and 40 m/s.

We need to calculate the resultant velocity

Using formula of resultant velocity

v=\sqrt{v_{x}^2+v_{y}^2}

Put the value into the formula

v=\sqrt{(30)^2+(40)^2}

v=50\ m/s[

We need to calculate the time

Using equation of motion

v = u+gt

v = 0+gt

t=\dfrac{v}{g}

Put the value into the formula

t=\dfrac{50}{9.8}

t=5.10\ sec

Hence, The time is 5.10 sec.

7 0
3 years ago
* A 5 kg ball is dropped from a height of 20 m. How much kinetic energy will it have 10 m above the ground? a. 490 J b. 392 J C.
Oksi-84 [34.3K]

Answer:

A. 490

Explanation:

soln

mass = m = 5kg

Height = h = 10m

Acceleration due to gravity = g = 9.8ms²

K.E = 1/2 × mass × (velocity)²

Recall from equations of motion

v² = u² + 2gh

Therefore,

K.E = 1/2 × mass × ( u² + 2gh)

K.E = 1/2 × 5 × ( 0² + 2×10×9.8)

K.E = 1/2 × 5 × 196

K.E = 1/2 × 980

K.E = 490 Joules

6 0
3 years ago
Why cant people with aids foght out the infection?
sveta [45]
They can fight the infection but not the disease
3 0
3 years ago
Read 2 more answers
An object of mass 30 kg is falling in air and experiences a force due to air resistance of 50 newtons. Calcuate the acceleration
rjkz [21]

Answer:

this answer you question

6 0
3 years ago
An electron is brought from rest infinitely far away to rest at point P located at a distance of 0.041 m from a fixed charge q.
torisob [31]

Answer:

The electric potential in volts is 1.618 x 10⁻¹⁷ V

Explanation:

The electric potential, in volts, at point P, can be calculated as follow;

Electric potential is the work done in moving a unit positive charge from infinity to a particular point in the electric field.

Thus, the work done in this process in moving the charge to point p is 101eV.

Convert this Volts = 101 × 1.602 x 10⁻¹⁹ V

                              = 1.618 x 10⁻¹⁷ V

Therefore, the electric potential in volts is 1.618 x 10⁻¹⁷ V

3 0
3 years ago
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