Answer:
75.9mL of 2.75M LiOH solution
Explanation:
Molarity is an unit of concentration defined as the ratio between moles and liters. And the molar mass of LiOH is 23.95g/mol. With this information, it is possible to know the volume of solution you should add to supply 5.0g, thus:
5.0g LiOH × (1mol / 23,95g) × (1L / 2.75mol) × (1000mL / 1L) = <em>75.9mL of 2.75M LiOH solution</em>
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Answer:
Explanation:
<u>1) Data:</u>
a) Hypochlorous acid = HClO
b) [HClO} = 0.015
c) pH = 4.64
d) pKa = ?
<u>2) Strategy:</u>
With the pH calculate [H₃O⁺], then use the equilibrium equation to calculate the equilibrium constant, Ka, and finally calculate pKa from the definition.
<u>3) Solution:</u>
a) pH
b) Equilibrium equation: HClO (aq) ⇄ ClO⁻ (aq) + H₃O⁺ (aq)
c) Equilibrium constant: Ka = [ClO⁻] [H₃O⁺] / [HClO]
d) From the stoichiometry: [CLO⁻] = [H₃O⁺] = 2.29 × 10 ⁻⁵ M
e) By substitution: Ka = (2.29 × 10 ⁻⁵ M)² / 0.015M = 3.50 × 10⁻⁸ M
f) By definition: pKa = - log Ka = - log (3.50 × 10 ⁻⁸) = 7.46
Answer:
Explanation:
the awnser is 37square root to the bse of 3
M
350 mL = 0.350 L
245.0g H2SO4 / 98.08 g/mol H2SO4
= 2.5 mol H2SO4
2.5 mol H2SO4 / 0.350 L = 7.14 M
Answer:
l=1
Explanation:
The angular momentum quantum number is a quantum number that describes the 'shape' of an orbital and tells us which subshells are present in the principal shell. A critical look at the electronic configuration of phosphorus at the ground state depicts the outermost electron to be in the P orbital where the angular quantum number ,l=1 .
