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Lina20 [59]
3 years ago
9

What mass of propane is necessary to react with the amount of oxygen calculated in the previous question? g C3H8

Chemistry
2 answers:
Iteru [2.4K]3 years ago
5 0

Answer:

the answer is 12.41

Explanation:

Don't worry about it

gladu [14]3 years ago
4 0

12.41g is the answer

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What did Ernest Rutherford’s gold foil experiment demonstrate about atoms? Their positive charge is located in a small region th
sergey [27]

Their positive charge is located in a small region that is called the nucleus.

Explanation:

Ernest Rutherford in his gold foil experiment was able to demonstrate that the nucleus is made up of positive charges which occupies a small and tiny nucleus.

Rutherford bombarded a thin gold foil with alpha particles from a radioactive source.

  1. He observed that all the particles passed through but a small portion was deflected back.
  2. This led to his proposition of the nuclear model the atom.

learn more:

Ernest Rutherford brainly.com/question/1859083

#learnwithBrainly

5 0
3 years ago
Describe Newton's Law of Viscosity and the constitutive behavior of non-Newtonian fluid
CaHeK987 [17]

Answer:

- "Newton’s viscosity law’s states that, the shear stress between adjacent fluid layers is proportional to the velocity gradients between the two layers".

- A non-Newtonian fluid is a fluid which the relationship between the shear stress and the velocity gradient is not properly defined by the Newton's viscosity law, thus, the behavior is not lineal but potential.

Explanation:

Hello, here the answers:

- "Newton’s viscosity law’s states that, the shear stress between adjacent fluid layers is proportional to the velocity gradients between the two layers" (taken from Kundu, P. K., Cohen, I. M., & Dowling, D. R. (2012). Fluid mechanics.), thus, it means that when you have a fluid with an acting-on-it share stress (an external force which move the fluid), the related velocity gradient (variation or change in velocity) at which the layers are moving are related as:

\pi =-v \frac{du}{dy}

Whereas \pi is the shear stress, v is the viscosity and the differential accounts for the change in the velocity in the arbitrary y coordinate.

- A non-Newtonian fluid is a fluid which the relationship between the shear stress and the velocity gradient is not properly defined by the Newton's viscosity law, thus, the behavior is not lineal but potential, based on:

\pi =-v (\frac{du}{dy})^n

Whereas n accounts for a decreasing or increasing behavior of the shear stress.

Best regards.

8 0
3 years ago
What volume would a 200.0 g sample of hydrogen sulfide gas occupy at stp?
GrogVix [38]
Answer is: Volume of hydrogen sulfide is 131,37 L.
m(H₂S) = 200,0 g.
n(H₂S) = m(H₂S) ÷ M(H₂S).
n(H₂S) = 200 g ÷ 34,1 g/mol.
n(H₂S) = 5,865 mol.
V(H₂S) = n(H₂S) · Vm.
V(H₂S) = 5,865 mol · 22,4 L/mol.
V(H₂S) = 131,37 L = 131,37 dm³.
n - amount of substance.
Vm - molar volume.
5 0
3 years ago
What cycloalkanes are present in a steroid ?
11Alexandr11 [23.1K]
Steroids are biologically very important compounds. They are made up of more that seventeen carbons. The structure of Steroid is comprised of a fused cycloalkane ring system. The simplest steroid and the main skeleton of all steroids is Gonane.

Gonane is made up of four cycloalkane rings i.e. tetracyclic hydrocarbon ring structure. Among these four rings 3 are cyclohexanes (designated as A, B and C) and one is cyclopentane (Designated as D). These four rings fuse to form a <span>cyclopentaperhydrophenanthrene.

The Nucleus (Gonane) of steroids along with some derivatives are shown below,</span>

3 0
3 years ago
Calculate the standard molar enthalpy of formation for Na2O(s), given that the standard enthalpy of formation for Na2O2(s) is -5
Anarel [89]

Answer:

- 416 kJ/mol

Explanation:

The standard enthalpy of the reaction (Δ H ∘ rxn) is independent of the pathway, so it can be calculated by the enthalpy of formation of the reactants and the products:

Δ H ∘ rxn = ∑n*Δ H ∘f products - ∑n*Δ H ∘f reactants

Where n is the number of moles in the balanced reaction. So, for the reaction given:

Na₂O(s) + 1/2O₂(g) → Na₂O₂(s)

Because O₂ is formed by only one elements, its Δ H ∘f is 0 kJ/mol:

-89.0 = (1*(-505) - (1*Δ H ∘fNa₂O)

Δ H ∘fNa₂O = -505 + 89

Δ H ∘fNa₂O = - 416 kJ/mol

3 0
4 years ago
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