Percent (%) Composition of CuO
Cu = 1 x 50g - Multiply by one as there is one Cu
O = 1 x 12.5g - Multiply by one as there is one O
CuO = 62.5g
% for Cu = 50g over 62.5 multiplied by 100 = 80%
% for O = 12.5g over 62.5 multiplied by 100 = 20%
Final Answer :
<em>Percent (%) Composition of CuO = </em>80% (Cu) & 20% (O)
Answer:
Decantation
Explanation:
Decantation is one of the process of separating mixture containing solid and liquid. In this process, gravity plays a very important role. The solid part of the mixture is allowed to settle down. The liquid is removed and separated in another container. It is a process that helps in the purification of the liquid. The particles that are insoluble settles down and is further subject to be separated from the mixture.
Answer:
the atomic mass number for boron is 5
Explanation:
hope it helps , pls mark me as brainliest
Remember that a conjugate acid-base pair will differ only by one proton.
None of the options you listed are conjugate acid-base pairs as none of them differ only by one proton (or H⁺)
An example of a conjugate acid-base pair would be NH₃ and NH₄⁺NH₃ + H₂O --> NH₄⁺ + OH⁻NH3 is the base, and NH₄⁺ is the conjugate acid