How many orbitals surround the nucleus in a neutral atom of sulfur (S)?

Chemistry

1 answer:

Leto [7]3 years ago

3 0

Explanation:

The atomic number of S is $16$

So,number of electrons in S is $16$

The electronic configuration of S is $2,8,6$

The orbital electronic configuration of S is $^{1}s_{2}^\text{ }^{2}s_{2}^\text{ }^{2}p_{x2}^\text{ }^{2}p_{y2}^\text{ }^{2}p_{z2}^\text{ }^{3}s_{2}^\text{ }^{3}p_{x2}^\text{ }^{3}p_{y1}^\text{ }^{3}p_{z1}^\text{ }$

So,the number of orbitals involved is 9.

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If each NADHNADH generates 3 ATPATP molecules and each FADH2FADH2 generates 2 ATPATP molecules, calculate the number of ATPATP m

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Answer:

$128~ATP$

Explanation:

The metabolic pathway by which energy can be obtained from a fatty acid is called <u>"beta-oxidation"</u>. In this route, acetyl-Coa is produced by removing <u>2 carbons</u> from the fatty acid for each acetyl-Coa produced. In other words, for each round, 1 acetyl Coa is produced and for each round 2 carbons are removed from the initial fatty acid. Therefore, the first step is to calculate the <u>number of rounds</u> that will take place for an <u>18-carbon fatty</u> acid using the following equation:

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$Number~of~Rounds=\frac{18}{2}-1~=~8$

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$Number~of~Acetyl-Coa=\frac{18}{2}~=~9$

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