Thomson used a beam of negatively charged particles.
the answer is d because it has the smallest wavelength
Acceleration I’m pretty sure
To solve this problem it is necessary to apply the concepts related to uniaxial deflection for which the training variable is applied, determined as

Where,
P = Tensile Force
L= Length
A = Cross sectional Area
E = Young's modulus
PART A) The elongation of the bar in a length of 200 mm caliber, could be determined through the previous equation, then



Therefore the elongaton of the rod in a 200mm gage length is 
PART B) To know the change in the diameter, we apply the similar ratio of the change in length for which,

Where,
Poission's ratio
= Lateral strain
= Linear strain




Therefore the change in diameter of the rod is 