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Dmitry [639]
3 years ago
7

8. What is the kinetic energy of a car that has a mass of 1000 kg and is moving at a speed of 30 m/s?

Physics
1 answer:
Snezhnost [94]3 years ago
6 0

Answer:

Hope it will help you :)

Explanation:

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bazaltina [42]

Answer:

The thyroid gland produces thyroxine (referred to as T4), which is a relatively inactive prohormone. The highly active hormone is triiodothyronine (referred to as T3).

Key actions of adrenaline include increasing the heart rate, increasing blood pressure, expanding the air passages of the lungs, enlarging the pupil in the eye (see photo), redistributing blood to the muscles and altering the body's metabolism, so as to maximise blood glucose levels (primarily for the brain).

7 0
3 years ago
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Which one of these is not a rock? A. granite B. Shale C. marble D. Diamond
saul85 [17]

DIAMONDS are NOT rocks. Diamonds are minerals, rocks are made up of many different fragments of minerals.

3 0
4 years ago
While riding on I-26 towards Columbia, your mother slams on the brakes, to avoid hitting the car in front of her. Both of your b
emmasim [6.3K]

Hi,

Newton's Law of Inertia explains this action because the resistance of the seat belt allows the change in its state of motion. So because the change of speed, your body moves forward but is restricted by the seat belt.

Have a great day!

4 0
3 years ago
A 3.0 \Omega Ω resistor is connected in parallel to a 6.0 \Omega Ω resistor, and the combination is connected in series with a 4
GarryVolchara [31]

Answer:

The power dissipated in the 3 Ω resistor is P= 5.3watts.

Explanation:

After combine the 3 and 6 Ω resistor in parallel, we have an 2 Ω and a 4 Ω resistor in series.

The resultating resistor is of Req=6Ω.

I= V/Req

I= 2A

the parallel resistors have a potential drop of Vparallel=4 volts.

I(3Ω) = Vparallel/R(3Ω)

I(3Ω)= 1.33A

P= I(3Ω)² * R(3Ω)

P= 5.3 Watts

7 0
4 years ago
I am really struggling with this question because I can't find anything on aphelion and perihelion, it's not a topic we went ove
Hoochie [10]

I have a strange hunch that there's some more material or previous work
that goes along with this question, which you haven't included here.

I can't easily find the dates of Mercury's extremes, but here's some of the
other data you're looking for:

Distance at Aphelion (point in it's orbit that's farthest from the sun):
<span><span><span><span><span>69,816,900 km
0. 466 697 AU</span>

</span> </span> </span> <span> Distance at Perihelion (</span></span><span>point in it's orbit that's closest to the sun):</span>
<span><span><span><span>46,001,200 km
0.307 499 AU</span> </span>

Perihelion and aphelion are always directly opposite each other in
the orbit, so the time between them is  1/2  of the orbital period.

</span><span>Mercury's Orbital period = <span><span>87.9691 Earth days</span></span></span></span>

1/2 (50%) of that is  43.9845  Earth days

The average of the aphelion and perihelion distances is

     1/2 ( 69,816,900 + 46,001,200 ) = 57,909,050 km
or
     1/2 ( 0.466697 + 0.307499) = 0.387 098  AU
 
This also happens to be 1/2 of the major axis of the elliptical orbit.


3 0
4 years ago
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