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Illusion [34]
3 years ago
12

How do warm ocean currents affect the weather?

Physics
1 answer:
Lilit [14]3 years ago
8 0

Answer:

the answer is D I believe

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A 2000-kg truck traveling at a speed of 6.0 m/s slows down to 4.0 m/s along a straight road. What
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Answer: -4000 kg • m/s

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NEED ANSWERS FAST! WHICH ONE IS IT?! ?!
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I used to wish that I can fly
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A wave is traveling through a medium. As it travels, it displaces particles of matter in the same direction as the wave is trave
Alexxandr [17]

<u>Answer</u>

longitudinal wave because the particles move parallel to the direction that the wave is traveling.


<u>Explanation</u>

There are 2 types of a wave, electromagnetic and mechanical wave. These waves can also be categorized into two, longitudinal ans transverse waves.

longitudinal wave is a wave whose particles vibration is in the direction of wave travel.

Transverse wave is a wave whose vibration of particles is perpendicular to the direction of wave travel.

7 0
3 years ago
Read 2 more answers
A charge of +3.0 mC is distributed uniformly along the circumference of a circle with a radius of 20 cm. How much external energ
Marat540 [252]

Answer:

Work done = 4584.9 J

Explanation:

given: q1=3.0 mC = 3.0 × 10⁻³ C, r = 20 cm = 0.20 m, q1 = 34μC = 34 × 10⁻⁶ C

Solution:

Formula for the potential difference at the center of the circle

P.E = K × q1 q2 /r   (Coulomb's constant k= 8.99 × 10⁹ N·m² / C²)

P.E = 8.99 × 10⁹ N·m² / C² × 3.0 × 10⁻³ C × 34 × 10⁻⁶ C /  0.20 m

P.E =  4584.9 J = Work done

3 0
3 years ago
If the phase angle for a block–spring system in SHM is ϕ and the block's position is given by x = xm cos(ωt + ϕ), what is the ra
matrenka [14]

<h2>K.E/P.E = m/k  tan²φ x ω²</h2>

Explanation:

The given position of block x = x₀ cos(ωt + φ)

The velocity of block  v = dx/dt = - x₀ sin(ωt + φ) x ω

The kinetic energy = 1/2 mv² = 1/2 m x₀² sin²(ωt + φ) x ω²

The potential energy of spring = 1/2 k x² , where k is the spring constant

Thus P.E = 1/2 x k x x₀² cos²(ωt + φ)

When t = 0

K.E = 1/2 m x₀²sin²φ x ω²

P.E = 1/2 k x₀² cos²φ

Dividing these , we have

K.E/P.E = m/k  tan²φ x ω²

7 0
3 years ago
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