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3 years ago

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Chemistry

2 answers:

Aleks04 [339]3 years ago

5 0

Answer:

Explanation:

you must add the 3 and 2 together because those are on the product side

mafiozo [28]3 years ago

4 0

5 oxygen atoms are there in the product

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a doctor's order is 0.125 g of ampicillin. the liquid suspension on hand contains 250 mg/5.0 ml. how many milliliters of the sus

disa [49]

0.125 g=(0.125 g)(1000 mg/1g)=125 mg.

Then, we need 125 mg of ampicillin.
5 ml of liquid suspension contains 250 mg of ampicilling , therefore:

5 ml----------------250 mg of ampicilling
x--------------------125 mg of ampicilling

x=(5 ml * 125 mg of ampicilling) / 250 mg of ampicilling=2.5 ml

Answer: we require 2.5 ml

5 0

3 years ago

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Magnesium (Mg): 1s22s22p63s2 longhand notation noble-gas notation

blsea [12.9K]

Answer: longhand notation

Explanation: I just did it on Edg

6 0

2 years ago

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If you had a 0.5 M KCl solution, how much solute would you have in moles, and what would the solute be?

Svetradugi [14.3K]

Answer:

37.25 grams/L.

Explanation:

Molarity (M) is defined as the no. of moles of solute dissolved per 1.0 L of the solution.

M = (no. of moles of KCl)/(volume of the solution (L))

∵ no. of moles of KCl = (mass of KCl)/(molar mass of KCl)

∴ M = [(mass of KCl)/(molar mass of KCl)]/(volume of the solution (L))

∴ (mass of KCl)/(volume of the solution (L)) = (M)*(molar mass of KCl) = (0.5 M)*(74.5 g/mol) = 37.25 g/L.

So, the grams/L of KCl = 37.25 grams/L.

6 0

3 years ago

An unknown compound contains 38.7 % calcium, 19.9 % phosphorus and 41.2 % oxygen. what is the empirical formula of this compound

Softa [21]

Answer: Ca3(PO4)2

Explanation:

We assume that the sample is 100.0 g.

The sample contains 38.7 g of Ca, 19.9 g of P, and 41.2 g of O as the proportions show.

Then we can calculate the number of moles of each component (n = m/atomic mass).

The number of moles of Ca = 38.7/40.078 = 0.96 mol.

The number of moles of P = 19.9/30.97 = 0.64 mol.

The number of moles of O = 41.2/15.99 = 2.75 mol.

Now, we can get the molar ratios of different components (Ca, P, and O) in the sample by dividing the number of moles of each component by the lower number of moles, that we should divide the number of moles by (0.64).

Ca: P: O = (0.96/0.64) : (0.64/0.64) : (2.75/0.64) = 1.5 : 1 : 4.

To avoid the fraction of the ratios, we can multiply all ratios by 2.0.

Now, the ratio of Ca : P : O will be 3 : 2 : 8.

That main the empirical formula of the compound is Ca3P2O8 which can be expressed as calcium phosphate (Ca3(PO4)2).

8 0

2 years ago

Which statement best describes what is taking place? Copper is being oxidized. Copper is being reduced. Copper is losing electro

Rasek [7]

Answer:

copper is being reduced

Explanation: I got 100% on the quiz good luck this class is hard lol

3 0

3 years ago