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Olenka [21]
3 years ago
13

"-3x" + 5 < "-10" Inequality 2: 7x + x - 4 > 28 Which of the following values makes BOTH inequalities TRUE? Select all tha

t apply! 12 "-5" −152 "-8.25" 23 48 325
Mathematics
1 answer:
zysi [14]3 years ago
6 0

Answer:

12, 23, 48, 325

Step-by-step explanation:

So, when given two inequalities and asked to find the values that make both true, it is considered a system of equations. To solve a system of equation, you have to graph the inequalities and find where they intersect.

Inequality 1:

(-3x) + 5 < (-10)

Inequality 2:

7x + x - 4 > 28

simplifies to: 8x - 4 > 28

When graphed, the inequalities don't intersect, but rather have a similar shaded area overlapping from the point of 5 and greater.

Answers that apply from given list would be:

12, 23, 48, 325

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consider this expression 7+3.4+2 what movements does this represent for Cecil walking on his tightrope? draw a diagram to show h
Lina20 [59]

Ok let me start it from here.

you are studying about properties of natural numbers or whole number or may be integers.

So , In this  Question you have to follow property of addition of integers.

⇒7+3=( You are at the point 7 on the number line or on the tight rope , you are moving (+3) on the right direction.) So you will reach at 7+1+1+1=10

⇒4+2=( You are at the point 4 on the number line or on the tight rope , you are moving (+2) on the right direction.) So you will reach at 4+1+1=6

In first case Cecil has taken total walk of 10 units and in second case Cecil has taken a walk of 10 units.

5 0
3 years ago
8/9k + 9/5 = -4 - 9/7k
Mamont248 [21]

Answer:

k=-1827/685

Step-by-step explanation:

8/9k+9/5=-4-9/7k

8/9k-(-9/7k)=-4-9/5

8/9k+9/7k=-20/5-9/5

56/63k+81/63k=-29/5

137/63k=-29/5

k=(-29/5)/(137/63)

k=(-29/5)(63/137)

k=-1827/685

7 0
3 years ago
Need help pleaseee i have a test on friday
larisa [96]

Answer:

x = 8

Step-by-step explanation:

Using the sine or cosine ratio in the right triangle and the exact value

sin30° = \frac{1}{2} , then

sin30° = \frac{opposite}{hypotenuse} = \frac{4}{x} = \frac{1}{2} ( cross- multiply )

x = 8

5 0
3 years ago
Consider the first five steps of the derivation of the Quadratic Formula.
lara31 [8.8K]

Answer:

Full proof below

Step-by-step explanation:

\displaystyle ax^2+bx+c=0\\\\ax^2+bx=-c\\\\x^2+\biggr(\frac{b}{a}\biggr)x=-\frac{c}{a}\\\\x^2+\biggr(\frac{b}{a}\biggr)x+\biggr(\frac{b}{2a}\biggr)^2=-\frac{c}{a}+\biggr(\frac{b}{2a}\biggr)^2\\\\x^2+\biggr(\frac{b}{a}\biggr)x+\frac{b^2}{4a^2}=-\frac{c}{a}+\frac{b^2}{4a^2}\\ \\\biggr(x+\frac{b}{2a}\biggr)^2=-\frac{4ac}{4a^2}+\frac{b^2}{4a^2}\\ \\\biggr(x+\frac{b}{2a}\biggr)^2=\frac{b^2-4ac}{4a^2}\\ \\x+\frac{b}{2a}=\pm\frac{\sqrt{b^2-4ac}}{2a}\\ \\x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

6 0
2 years ago
Please help me out with this..............
Andrews [41]

Answer:

C

Step-by-step explanation:

when x=0, y=0, so B is impossible

when X=2, Y=1,

and thus C is correct

6 0
3 years ago
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