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Olenka [21]
3 years ago
13

"-3x" + 5 < "-10" Inequality 2: 7x + x - 4 > 28 Which of the following values makes BOTH inequalities TRUE? Select all tha

t apply! 12 "-5" −152 "-8.25" 23 48 325
Mathematics
1 answer:
zysi [14]3 years ago
6 0

Answer:

12, 23, 48, 325

Step-by-step explanation:

So, when given two inequalities and asked to find the values that make both true, it is considered a system of equations. To solve a system of equation, you have to graph the inequalities and find where they intersect.

Inequality 1:

(-3x) + 5 < (-10)

Inequality 2:

7x + x - 4 > 28

simplifies to: 8x - 4 > 28

When graphed, the inequalities don't intersect, but rather have a similar shaded area overlapping from the point of 5 and greater.

Answers that apply from given list would be:

12, 23, 48, 325

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Evaluate the function f(x) = x2 + 3x for both of the following:
marissa [1.9K]
F(x)=x²+3x

f(0)=0²+3*0=0+0=0

Answer: f(0)=0

f(4)=4²+3*4=16+12=28

Answer: f(4)=28
6 0
3 years ago
Question:
faltersainse [42]

Answer:

The probability that a ship that is declared defecive is sound is 0.375

Step-by-step explanation:

Let P(A|B) denote the conditional probability of A given B. We will make use of the equation

P(A|B) = P(A) × P(B|A) / P(B)

We have the probabilities:

  • P(Declared Defective (detected) | Defective) = 0.95
  • P(not Detected | Defective) = 1-0.95=0.05
  • P(Declared Sound | Sound) = 0.97
  • P(Declared Defective |Sound) = 1-0.97=0.03
  • P(Defective)=0.05
  • P(Sound)= 1- 0.05 = 0.95

We can calculate:

P(Declared Defective)= P(Detected | Defective)×P(Defective) + P(Declared Defective |Sound) ×P(Sound) = 0.95×0.05 + 0.03×0.95=0.076

P(S | Declared Defective) =

(P(Sound) × P(Declared Defective | Sound)) / P(Declared Defective)

=0.95×0.03 /0.076 =0.375

3 0
3 years ago
The measurement of one angle of a right triangle is 34°.
Svetllana [295]
The third angle is 56 degrees because it is a right <u>triangle</u>, so the three angles will add up to 180 degrees.  Since it is a right triangle, you know one angle is 90 degrees.  All you have to do is add 90 and 34, and then subtract that from 180 to get your third angle.
4 0
3 years ago
A grocer sells milk chocolate at $2.90 per pound, dark chocolate at $4.90 per pound, and dark chocolate with almonds at $5.50 pe
daser333 [38]

Answer: milk chocolate = 10 pounds

Dark chocolate =15 pounds

Dark chocolate with almonds = 25 pounds.

Step-by-step explanation:

What we have here is a proportion problem.

Milk chocolate = $2.90

Dark chocolate = $4.90

Dark chocolate with almonds = $5.50

We are to have 50 pounds of mixed chocolate

Amount the grocer makes from this

= $4.80 × 50 = $240

However, we must consider how much the grocer would have made if he had sold them separately

Weight of milk chocolate = x

Weight of dark chocolate = y

Weight of dark chocolate with almond = z

x+y = z (according to the question)

x+y+z= 50

Equating the collective amount of each type of chocolate with the amount they all cost together

2.90x + 4.90y + 5.50z = 50(4.80)

2.90x + 4.90y + 5.50z = $240

But z = x + y

2.90x + 4.90y + 5.50 (x+y) = $240

2.90x + 4.90y + 5.50x + 5.50y = 240

8.40x + 10.40y = 240 .....eqn 1

Since x + y + z = 50

x + y = 50 - z

But x+ y = z

x + y = 50 - (x+y)

x + y = 50 - x - y

2x + 2y = 50

(Divide through by 2)

x+y = 25 ...... Eqn 2

y = 25 - x

Substitute for y in eqn2

8.4x + 10.4 (25-x) = 240

8.4x + 260 - 10.4x = 240

8.4x - 10.4x = 240 - 260

-2x = -20

x = 10 pounds

y = 25-x

y = 25-10

y=15pounds

x+y+z= 50

10+15+z= 50

25+z=50

z= 50-25

z = 25

6 0
3 years ago
In an election, ethan got 5 fewer votes than christohper,who got 3 more votes than olivia, who got 4 fewer votes than Ava.
Zina [86]

Answer:

110 votes

Step-by-step explanation:

110 votes

8 0
2 years ago
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