Whenever you want to write the equation of a parallel line through some point (h, k), you can ...
- remove any added constant in the original given equation
- replace x with (x-h)
- replace y with (y-k)
- rearrange the resulting equation to the form required by the problem.
Using this formula here, we get
... 2(y +5) = 3(x -2)
Your answer form requires you solve this for y.
... 2y + 10 = 3x -6 . . . . . eliminate parentheses
... 2y = 3x -16 . . . . . . . . subtract the constant on the left (10)
... y = (3/2)x -8 . . . . . . divide by 2
Answer:
Option A. 4, 4.5, 5, 5.5
Step-by-step explanation:
Left point: a=x=4
Right point: b=x=6
Range: r=b-a→r=6-4→r=2
Width of each of the four equal intervals: w=2/4→w=0.5
The first left endpoint is x1=a→x1=4
The second left endpoint is x2=x1+w→x2=4+0.5→x2=4.5
The third left endpoint is x3=x2+w→x3=4.5+0.5→x3=5
The fourth left endpoint is x4=x3+w→x4=5+0.5→x4=5.5
Then, the list is: x1, x2, x3, x4 = 4, 4.5, 5, 5.5
Answer:
90°
Step-by-step explanation:
Answer:
Minimum 8 at x=0, Maximum value: 24 at x=4
Step-by-step explanation:
Retrieving data from the original question:
![f(x)=x^{2}+8\:over\:[-1,4]](https://tex.z-dn.net/?f=f%28x%29%3Dx%5E%7B2%7D%2B8%5C%3Aover%5C%3A%5B-1%2C4%5D)
1) Calculating the first derivative

2) Now, let's work to find the critical points
Set this
0, belongs to the interval. Plug it in the original function

3) Making a table x, f(x) then compare
x| f(x)
-1 | f(-1)=9
0 | f(0)=8 Minimum
4 | f(4)=24 Maximum
4) The absolute maximum value is 24 at x=4 and the absolute minimum value is 8 at x=0.