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Vika [28.1K]
3 years ago
6

Select all of the ways you can describe the given polygon.

Mathematics
1 answer:
kvasek [131]3 years ago
6 0

Answer:

>regular triangle, we call equilateral triangles regular polygons.

>isosceles,  as an equilaterial triangle is a specific type of isosceles due to       more than one side being of equal length and angle.

>equilateral,  where all sides and angles are the same.

>acute,    as all 3 angles are less than 90

>equiangular.   equilateral triangles are also described as equiangular.

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Please help me I really need help
Oliga [24]

Answer:

Step-by-step explanation:

(1) 2x - 6y = -12

(2) x + 2y = 14

There is a -6y and a +2y. Since they have opposite signs, I'll try to eliminate the y terms. (That's my choice. There is more than one way to solve these.)

Multiply eq. (2) by 3:

3x + 6y = 42

Then add the result to eq. (1) to eliminate the y terms:

2x - 6y = -12

3x + 6y = 42

------------------

5x   = 30,  so x = 6

Now plug the value of x into eq. (2) and solve for y:

6 + 2y = 14

2y = 8

y = 4

Why did I use eq. (2) to solve for y? Because it's less work. I could have used eq. (1) instead:

2(6) - 6y = -12

12 - 6y = -12

-6y = -24

y = 4

More than one way to solve.

5 0
3 years ago
If <br>4x+(y+x)=180<br>what is x? what is y?​
uysha [10]

Step-by-step explanation:

4x+(y+x)=180\\\\\text{Solve for}\ x:\\\\4x+y+x=180\qquad\text{combine like terms}\\\\(4x+x)+y=180\qquad\text{subtract}\ y\ \text{from both sides}\\\\5x=180-y\qquad\text{divide both sides by 5}\\\\\dfrac{5x}{5}=\dfrac{180-y}{5}\\\\\boxed{x=\dfrac{180-y}{5}}\\\\\text{Solve for}\ y:\\\\5x+y=180\qquad\text{subtract}\ 5x\ \text{from both sides}\\\\\boxed{y=180-5x}

7 0
3 years ago
Y=2x+b in y=MX+b form
Fynjy0 [20]
It would appear your original equation is in Y=MX+b form, where M=2
4 0
3 years ago
How many terms are in this expression?<br> 8+6k+10n
galina1969 [7]

two me plus you equals one <3


4 0
3 years ago
Read 2 more answers
A shopping mall parking garage charges $2 for the first half hour and $1.20 for each additional half hour (even if it is under 3
Neko [114]

You can park in the garage for 5 hours 30 minutes

<em><u>Solution:</u></em>

Given that, shopping mall parking garage charges $2 for the first half hour and $1.20 for each additional half hour (even if it is under 30 minutes)

Therefore,

Cost for first half an hour = $ 2

Cost for each additional half an hour = $ 1.20

Let "x" be the number of each additional half hour

Therefore, total cost to pay is given as:

Total cost = Cost for first half an hour + (Cost for each additional half an hour)(number of each additional half hour)

Total cost = 2 + 1.20x

<em><u>Given you have $ 8 in cash</u></em>

8 = 2 + 1.20x\\\\1.20x = 8 - 2\\\\1.20x = 6\\\\x = \frac{6}{1.20}\\\\x = 5

Total hours parked = first half an hour + 5

Thus you can park in the garage for 5 hours 30 minutes

4 0
3 years ago
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