Answer:
The probability that can afford to spend between $800 and $900
P(800≤X≤900) = 0.6826
The percentage of that can afford to spend between $800 and $900
P(800≤X≤900) = 68 percentage
Step-by-step explanation:
<u><em>Step(i):-</em></u>
Given that the mean of the Normal distribution = $850
Given that the standard deviation of the Normal distribution = $50
Let 'X' be a random variable in a normal distribution
Let x₁ = 800

Let x₂ =850

<u><em>Step(ii):-</em></u>
The probability that can afford to spend between $800 and $900
P(800≤X≤900) = P(-1≤Z≤1)
= P(Z≤1) - P(Z≤-1)
= 0.5 + A(1) - (0.5 - A(-1))
= A(1) +A(-1)
= 2× A(1) (∵ A(-1) =A(1)
= 2 × 0.3413
= 0.6826
The percentage of that can afford to spend between $800 and $900
P(800≤X≤900) = 68 percentage
The equation for the area of a triangle is A= b*h /2. So, plug in your known variables, and you get 270in^2= b*30 /2. First you multiply by 2 to cancel out the division for 2, which gets you 540= b* 30. To get "b" by itself, divide both sides by 30, giving you <u>18=b</u>.
To check this, plug in your new known variable, as 270= 18* 30 /2. This will equal as 270=270, confirming 18in as the correct measurement.
Let x be the number of people at University B
x + (x+3.5) = 9.5
2x +3.5 = 9.5
2x = 6
x = 3 million students at University B
x + 3.5 = 3 + 3.5 = 6.5 million students at University A
Answer:
6
Step-by-step explanation:
=
·
=
³ ·
³ = 2 x 3 = 6
It’s 42 but Carrier the 2