Select true or false: the definition of free radicals is molecular fragments having one or more unpaired electrons.

This is very urgent please hurry!!?!!??!

yawa3891 [41]

Answer:

The greatest acceleration when the unbalanced force is applied will be experienced in :

A) The box with a mass of 2 kg

Explanation:

According to second law of motion the external unbalanced force is directly proportional to rate of change of momentum.

F = (Final momentum - initial momentum)/time

or

Force is equal to the product of mass and acceleration

F = m x a

Here a= acceleration

m = mass of the object

If Force is constant then acceleration is inversely proportional to mass

$a =\frac{F}{m}$

A) The box with a mass of 2kg

F = 8 N

$a =\frac{8}{2}$

a = 4 m/s2

B) The box with the mass of 4kg

$a =\frac{8}{4}$

a = 2 m/s2

C) The box with a mass of 6kg

$a =\frac{8}{6}$

a = 1.33 m/s2

D) The box with a mass of 8kg

$a =\frac{8}{8}$

a = 1 m/s2

3 0

3 years ago

What is a displacement reactions

Alisiya [41]

<h2><u>Question</u><u>:</u>-</h2>

$\textsf{what is a displacement reactions? }$

<h2><u>Answer</u><u>:</u></h2>

$\large \underbrace{ \underline{ \sf Displacement \: reaction}}$

The reaction in which more reactive element replace a less reactive element from its compound is called displacement reaction.

Ex:-

$\bold{\large Zn+HCl \longrightarrow ZnCl_2+H_2}$

6 0

2 years ago

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CO2(g)+CCl4(g)⇌2COCl2(g) Calculate ΔG for this reaction at 25 ∘C under these conditions: PCO2PCCl4PCOCl2===0.140 atm0.185 atm0.7

padilas [110]

<u>Answer:</u> The $\Delta G$ for the reaction is 54.425 kJ/mol

<u>Explanation:</u>

For the given balanced chemical equation:

$CO_2(g)+CCl_4(g)\rightleftharpoons 2COCl_2(g)$

We are given:

$\Delta G^o_f_{CO_2}=-394.4kJ/mol\\\Delta G^o_f_{CCl_4}=-62.3kJ/mol\\\Delta G^o_f_{COCl_2}=-204.9kJ/mol$

To calculate $\Delta G^o_{rxn}$ for the reaction, we use the equation:

$\Delta G^o_{rxn}=\sum [n\times \Delta G_f(product)]-\sum [n\times \Delta G_f(reactant)]$

For the given equation:

$\Delta G^o_{rxn}=[(2\times \Delta G^o_f_{(COCl_2)})]-[(1\times \Delta G^o_f_{(CO_2)})+(1\times \Delta G^o_f_{(CCl_4)})]$

Putting values in above equation, we get:

$\Delta G^o_{rxn}=[(2\times (-204.9))-((1\times (-394.4))+(1\times (-62.3)))]\\\Delta G^o_{rxn}=46.9kJ=46900J$

Conversion factor used = 1 kJ = 1000 J

The expression of $K_p$ for the given reaction:

$K_p=\frac{(p_{COCl_2})^2}{p_{CO_2}\times p_{CCl_4}}$

We are given:

$p_{COCl_2}=0.735atm\\p_{CO_2}=0.140atm\\p_{CCl_4}=0.185atm$

Putting values in above equation, we get:

$K_p=\frac{(0.735)^2}{0.410\times 0.185}\\\\K_p=20.85$

To calculate the gibbs free energy of the reaction, we use the equation:

$\Delta G=\Delta G^o+RT\ln K_p$

where,

$\Delta G$ = Gibbs' free energy of the reaction = ?

$\Delta G^o$ = Standard gibbs' free energy change of the reaction = 46900 J

R = Gas constant = $8.314J/K mol$

T = Temperature = $25^oC=[25+273]K=298K$

$K_p$ = equilibrium constant in terms of partial pressure = 20.85

Putting values in above equation, we get:

$\Delta G=46900J+(8.314J/K.mol\times 298K\times \ln(20.85))\\\\\Delta G=54425.26J/mol=54.425kJ/mol$

Hence, the $\Delta G$ for the reaction is 54.425 kJ/mol

7 0

2 years ago

The characteristic functional groups of a protein are _____.

V125BC [204]

Answer:

$\boxed{\text{amide groups}}$

Explanation:

A protein is a long chain of amino acids linked together by amide groups.

The general structure is

$\rm \left[-NHCHR-\underbrace{\hbox{CO-NH}}_{\hbox{amide group}}-CHRCO-\right]_{n}$

4 0

2 years ago

Covalent bonds are formed when valence electrons are

mamaluj [8]

It’s b. Shared between two atoms.

5 0

2 years ago

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