Ok so, I assume this is 6 times 501
     501
   x    6
-------------
   3006
5 x 6 = 30
6 x 0 = 0
6 x 1 = 6
        
                    
             
        
        
        
Answer:
In a certain Algebra 2 class of 30 students, 22 of them play basketball and 18 of them play baseball. There are 3 students who play neither sport. What is the probability that a student chosen randomly from the class plays both basketball and baseball?
I know how to calculate the probability of students play both basketball and baseball which is 1330 because 22+18+3=43 and 43−30 will give you the number of students plays both sports.
But how would you find the probability using the formula P(A∩B)=P(A)×p(B)?
Thank you for all of the help.
That formula only works if events A (play basketball) and B (play baseball) are independent, but they are not in this case, since out of the 18 players that play baseball, 13 play basketball, and hence P(A|B)=1318<2230=P(A) (in other words: one who plays basketball is less likely to play basketball as well in comparison to someone who does not play baseball, i.e. playing baseball and playing basketball are negatively (or inversely) correlated)
So: the two events are not independent, and so that formula doesn't work.
Fortunately, a formula that does work (always!) is:
P(A∪B)=P(A)+P(B)−P(A∩B)
Hence:
P(A∩B)=P(A)+P(B)−P(A∪B)=2230+1830−2730=1330
 
        
             
        
        
        
Answer:
$1200
Step-by-step explanation:
The clustering method for estimation is a method used for estimating the sums and products of numbers. This method is used when the numbers that are to be multiplied or added are near in value to a single number.
Given the money raised by six fund raisers:
$212, $205, $206, $190, $188, and $195
The numbers are to be added to find the total money raised. i.e.:
$212 + $205 + $206 + $190 + $188 + $195
But all the numbers are close to $200. Hence:
Using clustering method = $200 + $200 + $200 + $200 + $200 + $200 = 6 * $200 = $1200
 
        
             
        
        
        
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Answer:
 
Then the probability that exactly 6 bridges in the sample are structurally deficient is 0.1063 or 10.63%
Step-by-step explanation:
Let X the random variable of interest "number of bridges in the sample are structurally deficient", on this case we now that:
 
The probability mass function for the Binomial distribution is given as:
 
Where (nCx) means combinatory and it's given by this formula:
 
And we want to find this probability:

And if we use the probability mass function and we replace we got:
 
Then the probability that exactly 6 bridges in the sample are structurally deficient is 0.1063 or 10.63%