Answer:
In the attachment.
Step-by-step explanation:
Rewrite
as a
. Then mark each set with different color and take the intersection of these.
Answer:
(x, y) = (2, 5)
Step-by-step explanation:
I find it easier to solve equations like this by solving for x' = 1/x and y' = 1/y. The equations then become ...
3x' -y' = 13/10
x' +2y' = 9/10
Adding twice the first equation to the second, we get ...
2(3x' -y') +(x' +2y') = 2(13/10) +(9/10)
7x' = 35/10 . . . . . . simplify
x' = 5/10 = 1/2 . . . . divide by 7
Using the first equation to find y', we have ...
y' = 3x' -13/10 = 3(5/10) -13/10 = 2/10 = 1/5
So, the solution is ...
x = 1/x' = 1/(1/2) = 2
y = 1/y' = 1/(1/5) = 5
(x, y) = (2, 5)
_____
The attached graph shows the original equations. There are two points of intersection of the curves, one at (0, 0). Of course, both equations are undefined at that point, so each graph will have a "hole" there.
<span> 3(x+2y)+5x−y+1
Use distributive property
3x+6y+5x-y+1
Add 5x to 3x
8x+6y-y+1
Subtract y from 6y
Final Answer: 8x+5y+1</span>
I think the answer is 6 and 5 because 6+5=11 and 6-5=1