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attashe74 [19]
3 years ago
14

Please answerr!! Math

Mathematics
1 answer:
Morgarella [4.7K]3 years ago
4 0

Answer:

a

Step-by-step explanation:

i got it on a test

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Unit rate 45 points in 3 games
Nikolay [14]

15

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Expansion Numerically Impractical. Show that the computation of an nth-order determinant by expansion involves multiplications,
posledela

Answer:

  • number of multiplies is n!
  • n=10, 3.6 ms
  • n=15, 21.8 min
  • n=20, 77.09 yr
  • n=25, 4.9×10^8 yr

Step-by-step explanation:

Expansion of a 2×2 determinant requires 2 multiplications. Expansion of an n×n determinant multiplies each of the n elements of a row or column by its (n-1)×(n-1) cofactor determinant. Then the number of multiplies is ...

  mpy[n] = n·mp[n-1]

  mpy[2] = 2

So, ...

  mpy[n] = n! . . . n ≥ 2

__

If each multiplication takes 1 nanosecond, then a 10×10 matrix requires ...

  10! × 10^-9 s ≈ 0.0036288 s ≈ 0.004 s . . . for 10×10

Then the larger matrices take ...

  n=15, 15! × 10^-9 ≈ 1307.67 s ≈ 21.8 min

  n=20, 20! × 10^-9 ≈ 2.4329×10^9 s ≈ 77.09 years

  n=25, 25! × 10^-9 ≈ 1.55112×10^16 s ≈ 4.915×10^8 years

_____

For the shorter time periods (less than 100 years), we use 365.25 days per year.

For the longer time periods (more than 400 years), we use 365.2425 days per year.

8 0
4 years ago
Find the area of the shaded region. The graph depicts the standard normal distribution with mean 0 and standard deviation 1
Digiron [165]

Answer:

P(z

And the best option would be:

0.8708

Step-by-step explanation:

We assume that the distribution for the random variable is:

X \sim N (\mu=0 , \sigma=1)

For this case we want to calculate the following probability:

P(z

And we can use the normal standard distribution or excel and we got:

P(z

And the best option would be:

0.8708

8 0
3 years ago
Leslie need 48 ounces of charcoal. How many pounds should she buy?
andreyandreev [35.5K]
16 ounces= 1 pound
48÷16=3
3 pounds
7 0
3 years ago
9. Triangle Construction pays Square Insurance $5,980
xxTIMURxx [149]

The triangle pay $32 more for that day than it paid per day during the first period of time.

Step-by-step explanation:

The given is,

              Triangle Construction pays Square Insurance $5,980

               To insure a construction site for 92 days

               To extend the  insurance beyond the 92 days costs $97 per day

               Triangle extends the insurance by 1 day

Step:1

              Insurance per day from the 92 days period,

                                                                           = \frac{Total insuratio for 92 days}{Period}

               Where, Total insurance for 92 days = $ 5,980

                                                               Period = 92 days

               From the values, equation becomes,

                                                                            =\frac{5980}{92}

                                                                           = $ 65 per day

Step:2

              Insurance per day after the 92 days,

                                                                           = $ 97

               Amount Pay for that day than it paid per day during the first period of time,

                                                                            =(97-65)

                                                                           = $32

Result:

             The triangle pay $32 more for that day than it paid per day during the first period of time, if  the Triangle Construction pays Square Insurance $5,980 to insure a construction site for 92 days and to extend the  insurance beyond the 92 days costs $97 per day.

                                                                         

8 0
3 years ago
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