The median is 11, so 11 is part of the data set. We have an odd number of values (5) which is why the median is part of the data set.
The mode is 12. The value 12 shows up the most times. Let's say it shows up twice. So far the data set is {11, 12, 12}
Let's introduce two more numbers x and y
The new data set is {x, y, 11, 12, 12}
Add up the five values and then divide by 5. We want this result to be equal to 10
(x+y+11+12+12)/5 = 10
(x+y+35)/5 = 10
x+y+35 = 10*5
x+y+35 = 50
x+y = 50-35
x+y = 15
So we don't know what x or y is, but we know that they must add to 15. So all you have to do is list two numbers that add to 15. One such pair is x = 6 and y = 9. Another pair is x = 7 and y = 8. There are infinitely many possibilities if you can use any real number.
So one possible set is {6, 9, 11, 12, 12}
Another possible set is {7, 8, 11, 12, 12}
Answer:
6.552×10³×10
6.552×10^3+1
6.552×10^4 is the standard form
i hope this will help you :)
Answer:
In case (a) car makes 105° turn.
In case (b) car makes 75° turn.
In case (c) car makes 105° turn.
Step-by-step explanation:
Figure is redrawn To explain properly (in attachment)
Given : streets are parallel means
║
,
AB - 4th street , CD - 3rd street and XY - King Ave.
∠XLA = 75°
To find : (a) ∠XLB
(b) ∠LMD (left onto 3rd streat means left of car)
(c) ∠YMD (right means right side of car)
∠XLB + ∠XLA = 180° (Linear Pair = 2 adjacent angles are
supplementary)
∠XLB + 75° = 180°
∠XLB = 180 - 75
∠XLB = 105°
∴ In case (a) car makes 105° turn.
∠LMD = ∠XLA = 75° (Corresponding angles of parallel lines are equal)
∠LMD = 75°
∴ In case (b) car makes 75° turn.
∠YMD + ∠LMD = 180° (Linear Pair = 2 adjacent angles are
supplementary)
∠YMD + 75° = 180°
∠YMD = 180 - 75
∠YMD = 105°
∴In case (c) car makes 105° turn.