Which expression is equivalent to 8a + 14?

a number is selected at random from set (2,3,45,6,7,8,9,and 10). which event covers the entire sample space of this experiment ?

ki77a [65]

I'm not sure I understand the question. Is this worded correctly?

8 0

3 years ago

What system the system that is made up of the heart,blood, and blood vessels is called the ____ this is for sceince but i cant f

Fiesta28 [93]

Answer:

Cardiovascular system

Step-by-step explanation:

8 0

2 years ago

Suppose a particular type of cancer has a 0.9% incidence rate. Let D be the event that a person has this type of cancer, therefo

natita [175]

Answer:

There is a 12.13% probability that the person actually does have cancer.

Step-by-step explanation:

We have these following probabilities.

A 0.9% probability of a person having cancer

A 99.1% probability of a person not having cancer.

If a person has cancer, she has a 91% probability of being diagnosticated.

If a person does not have cancer, she has a 6% probability of being diagnosticated.

The question can be formulated as the following problem:

What is the probability of B happening, knowing that A has happened.

It can be calculated by the following formula

$P = \frac{P(B).P(A/B)}{P(A)}$

Where P(B) is the probability of B happening, P(A/B) is the probability of A happening knowing that B happened and P(A) is the probability of A happening.

In this problem we have the following question

What is the probability that the person has cancer, given that she was diagnosticated?

So

P(B) is the probability of the person having cancer, so $P(B) = 0.009$

P(A/B) is the probability that the person being diagnosticated, given that she has cancer. So $P(A/B) = 0.91$

P(A) is the probability of the person being diagnosticated. If she has cancer, there is a 91% probability that she was diagnosticard. There is also a 6% probability of a person without cancer being diagnosticated. So

$P(A) = 0.009*0.91 + 0.06*0.991 = 0.06765$

What is the probability that the person actually does have cancer?

$P = \frac{P(B).P(A/B)}{P(A)} = \frac{0.91*0.009}{0.0675} = 0.1213$

There is a 12.13% probability that the person actually does have cancer.

3 0

2 years ago

Samantha read 22 books in 4 months. How many books would she read in 10 months?

kari74 [83]

Well first let's find out how many books she reads in 1 month.
1) 22 (books) ÷4 (months)=5.5 she reads 5.5 books in one month.
Now we multiply 5.5 by the amount of months she will be reading.
2) 5.5 (books) ×10 ( months)=55 books
SAMANTHA WILL READ 55 BOOKS IN 10 MONTHS

8 0

3 years ago

Find the average rate of change of the function from <img src="https://tex.z-dn.net/?f=x_%7B1%7D" id="TexFormula1" title="x_{1}"

meriva

Hi there!

$\large\boxed{\text{Average rate} = 2}$