An equation in the form of slope intercept is written as y=mx+b. That means that we need to get y positive, which we can do by adding 3y to each side, and then subtracting 3 from each side to get y by itself. Doing all of these steps, the equation becomes 3y=5x-3. But, we're not done because we still need to get y equal to one, which we can do by dividing each side of the equation by 3. This makes the equation become y=5/3x-1.
The graph of the equation looks like this:
Answer:
D) None of the above
Step-by-step explanation:
These are no supplementary or complimentary because they do not add up to 180 and to be vertical they would have to be across from each other
No, Jonah is not correct. The answer is shown in the picture.
Answer:
(-1, 0), (2, 0), (3, 0)
Step-by-step explanation:
x-intercept of a line is defined by a point where y = 0.
So the point in the form of (x, 0) will be the x-intercept of the given continuous function.
From the table attached,
For x = -1, f(-1) = 0
For x = 2, f(2) = 0
For x = 3, f(3) = 0
Points (-1, 0), (2, 0) and (3, 0) are the x-intercepts of the continuous function f(x).
An aritmetic sequence is like this
where a1=first term and d=common difference
geometric is
where a1=first term and r=common ratio
can it be both aritmetic and geometric
hmm, that means that the starting terms should be the same
therfor we need to solve
what values of d and r make all natural numbers of n true?
are there values that make all natural numbers for n true?
when n=1, then d(1-1)=0 and r^(1-1)=1, so already they are not equal
the answer is no, a sequence cannot be both aritmetic and geometric
