15 electricians worked for 24 days to the whole job, now, there are 15 of them, so on any given day, each electrician worked one whole day, in 24 days, that one electrician worked 24 days total.
now, there were 15 electricians on any given day though, since each one of them worked the whole day that one day, so the "days work worth" on a day is 15, so the house gets 15days worth of work because of that.
so how many "days worth" did all 15 do on the 24 days, well, 15+15+15+15+15+15+15+15+15+15+15+15+15+15+15+15+15+15+15+15+15+15+15+15, namely 15 * 24, or 360 days worth of work.
since it takes 360 days worth of work to do the whole wiring, in how many days would 18 electricians do it? 360/18.
Firstly arrange data from smaller to greater data point:
4 5 6 9 10 11 12 13 15 16
Secondly find the middle value: In our case the number of data is even, so to get the middle value we have to find the mean (average) between 10 & 11, that is 10.5. So the rank of the Median is10.5
area of square = 4ft²
a s area of square = length×lenght
let lenght =x
so area = x²
x²= 4ft²
taking square root
x=2 ftSo lebght of each side is 2 ft.
Answer:
-1/2
Step-by-step explanation:
Given:
Find the common denominator for the fractions, which is 6. Rewrite 1/3 as 2/6.
Combine like terms.
Simplify.
-0.5x = 1/4
Divide both sides by -0.5.
x = -1/2 = -0.5
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∆PQR and ∆SQT are similar, so corresponding sides occur in fixed ratios with one another. This means
SQ / PQ = ST / PR
Solve for x :
8 / ((x + 5) + 8) = (x - 9) / 21
8 / (x + 13) = (x - 9) / 21
168 = (x - 9) (x + 13)
168 = x² + 4x - 117
x² + 4x - 285 = 0
(x + 19) (x - 15) = 0
⇒ x = -19 or x = 15
But x can't be smaller than 9, otherwise ST = x - 9 would be a negative length. So x = 15.
