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sergeinik [125]
2 years ago
6

Write the word sentence as an inequality. Then solve the inequality.

Mathematics
1 answer:
skelet666 [1.2K]2 years ago
5 0
3-x15 ?? Or 3-x+15 I’m not so sure I’m really bad at this but I really want to try to help I’m sorry if u got it wrong it would be my fault sorry
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When performing tests involving two or more populations it is important to specify which population is population 1 and which is
iris [78.8K]
Answer:



a. True







Explain:

3 0
2 years ago
Can someone please help me <br>a<br>show your work please ​
sertanlavr [38]

Answer:

x= 3

Step-by-step explanation:

19x-5=7+15x

19x-15x=7+5

4x=12

x=12/4

x=3

8 0
3 years ago
Read 2 more answers
What value of b will cause the system to have an infinite number of solutions?
irga5000 [103]

b must be equal to -6  for infinitely many solutions for system of equations y = 6x + b and -3 x+\frac{1}{2} y=-3

<u>Solution: </u>

Need to calculate value of b so that given system of equations have an infinite number of solutions

\begin{array}{l}{y=6 x+b} \\\\ {-3 x+\frac{1}{2} y=-3}\end{array}

Let us bring the equations in same form for sake of simplicity in comparison

\begin{array}{l}{y=6 x+b} \\\\ {\Rightarrow-6 x+y-b=0 \Rightarrow (1)} \\\\ {\Rightarrow-3 x+\frac{1}{2} y=-3} \\\\ {\Rightarrow -6 x+y=-6} \\\\ {\Rightarrow -6 x+y+6=0 \Rightarrow(2)}\end{array}

Now we have two equations  

\begin{array}{l}{-6 x+y-b=0\Rightarrow(1)} \\\\ {-6 x+y+6=0\Rightarrow(2)}\end{array}

Let us first see what is requirement for system of equations have an infinite number of solutions

If  a_{1} x+b_{1} y+c_{1}=0 and a_{2} x+b_{2} y+c_{2}=0 are two equation  

\Rightarrow \frac{a_{1}}{a_{2}}=\frac{b_{1}}{b_{2}}=\frac{c_{1}}{c_{2}} then the given system of equation has no infinitely many solutions.

In our case,

\begin{array}{l}{a_{1}=-6, \mathrm{b}_{1}=1 \text { and } c_{1}=-\mathrm{b}} \\\\ {a_{2}=-6, \mathrm{b}_{2}=1 \text { and } c_{2}=6} \\\\ {\frac{a_{1}}{a_{2}}=\frac{-6}{-6}=1} \\\\ {\frac{b_{1}}{b_{2}}=\frac{1}{1}=1} \\\\ {\frac{c_{1}}{c_{2}}=\frac{-b}{6}}\end{array}

 As for infinitely many solutions \frac{a_{1}}{a_{2}}=\frac{b_{1}}{b_{2}}=\frac{c_{1}}{c_{2}}

\begin{array}{l}{\Rightarrow 1=1=\frac{-b}{6}} \\\\ {\Rightarrow6=-b} \\\\ {\Rightarrow b=-6}\end{array}

Hence b must be equal to -6 for infinitely many solutions for system of equations y = 6x + b and  -3 x+\frac{1}{2} y=-3

8 0
3 years ago
Ifx &lt;5 and x &gt; C, give a value of c such that there
professor190 [17]

Answer:

For c=5 there are not solutions for the compound inequality

Step-by-step explanation:

we know that

In the compound inequality

x < 5 -----> inequality A

x > c -----> inequality B

The solution of the system of inequalities must satisfy inequality A and must satisfy inequality B

so

If c=5

then

There is no solution that satisfies both inequalities simultaneously.

therefore

For c=5 there are not solutions for the compound inequality

4 0
3 years ago
What is the answer to this question
Airida [17]

the answer would be 67,127 because the number in the ones would be 7 and the tens number would be 2 since it wouldn't more than 1.

67,102

67,135

     1-7

67,127

8 0
3 years ago
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