Answer:
Explanation:
Translation:
- <em>What volume will 12g of iron occupy?</em>
<em></em>
<h2>Solution</h2>
<em />
<em>Iron</em> is a solid substance at room temperature. You can find the <em>volume</em> of solids (and of not solids) using the density.
You can obtaindthe density of most pure substances in the internet. The density of<em> iron</em> at room temperature is 7.874 g/cm³.
Thus, substituting in the formula, you get:
The answer is rounded to two significant figures because the input, 12g, has two significant figures.
The electrical charge of an atom having 15 proton, 14 neutrons and 16 electrons is -1. The correct option is D.
What is an atom?
An atom is the smallest unit of any matter which comprises of central nucleus and electrons revolving around the nucleus in definite energy shells. The atom is made up of protons, neutrons and electrons.
The electrical charge of an atom can be calculated as,
Charge of an atom = number of protons - number of electrons
Charge = 15 - 16 = -1.
The neutrons are neutral and do not contribute to the charge, the protons are positively charged and electrons are negatively charged in an atom.
Therefore, the charge of an atom with 15 protons, 14 neutrons and 16 electrons is -1. The correct answer is option D.
To learn more about atom click on the given link brainly.com/question/6258301
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Hi there,
the answer to the blank is: boiling point
When a liquid is heated, the temperature stops rising at the liquid's boiling point.
Hope this is correct :)
Have a great day
Answer: The enthalpy of combustion, per mole, of butane is -2657.4 kJ
Explanation:
The balanced chemical reaction is,
The expression for enthalpy change is,
![\Delta H=[n\times H_f_{products}]-[n\times H_f_{reactants}]](https://tex.z-dn.net/?f=%5CDelta%20H%3D%5Bn%5Ctimes%20H_f_%7Bproducts%7D%5D-%5Bn%5Ctimes%20H_f_%7Breactants%7D%5D)
Putting the values we get :
![\Delta H=[8\times H_f_{CO_2}+10\times H_f_{H_2O}]-[2\times H_f_{C_4H_{10}+13\times H_f_{O_2}}]](https://tex.z-dn.net/?f=%5CDelta%20H%3D%5B8%5Ctimes%20H_f_%7BCO_2%7D%2B10%5Ctimes%20H_f_%7BH_2O%7D%5D-%5B2%5Ctimes%20H_f_%7BC_4H_%7B10%7D%2B13%5Ctimes%20H_f_%7BO_2%7D%7D%5D)
![\Delta H=[(8\times -393.5)+(10\times -241.82)]-[(2\times -125.7)+(13\times 0)]](https://tex.z-dn.net/?f=%5CDelta%20H%3D%5B%288%5Ctimes%20-393.5%29%2B%2810%5Ctimes%20-241.82%29%5D-%5B%282%5Ctimes%20-125.7%29%2B%2813%5Ctimes%200%29%5D)
2 moles of butane releases heat = 5314.8 kJ
1 mole of butane release heat = 
Thus enthalpy of combustion per mole of butane is -2657.4 kJ
please have look at Periodic table , you will solve it yourself !
