Answer:
Table 1 and 2 represent a function
Step-by-step explanation:
Given
<em>Table 1</em>
x 5 10 11
y 3 9 15
<em></em>
<em>Table 2</em>
x 5 10 11
y 3 9 9
<em>Table 3</em>
x 5 10 10
y 3 9 15
Required
Determine which of the tables represent that y is a function of x
For a relation to be a function; the x values must be unique.
In other words, each x value must not be repeated;
Having said that;
Analyzing Table 1
<em>Table 1</em>
x 5 10 11
y 3 9 15
<em></em>
Note that the x rows are unique as no value were repeated;
Hence, Table 1 is a function
<em>Table 2</em>
x 5 10 11
y 3 9 9
Note that the x rows are unique as no value were repeated;
Hence, Table 2 is a function
<em>Table 3</em>
x 5 10 10
y 3 9 15
Note that the x rows are not unique because 10 was repeated twice;
Hence, Table 3 is not a function
Answer:
x1 = 6 + 2√6 or x2 = 6 - 2√6
Step-by-step explanation:
x² - 12x + 12 = 0
We need to use formula:
a² - 2ab + b² = (a - b)².
x² - 12x = - 12
x² - 2*6x + 6²- 6² = - 12
(x - 6)² - 36 = -12
(x - 6)² = - 12 + 36
(x -6)² = 24
(x - 6) = √24 or (x-6) = -√24
(x - 6) = 2√6 or (x-6) = - 2√6
x = 6 + 2√6 or x = 6 - 2√6
Answer: 5/6
Step-by-step explanation:
