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san4es73 [151]
3 years ago
14

Answer is D

Chemistry
2 answers:
Shkiper50 [21]3 years ago
8 0
(D is associated with the characteristic
Tanya [424]3 years ago
7 0

Option D : Strong bonds in reactant molecules

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Why do many parasites eventually need new hosts?
Maslowich
Parasite lives off the host so if the host dies, they are forced to look for another host. They can also leave its host if the parasite kills its host when it finds a new host, because if the parasite does not have a host its dies off.
Hope this can help explain
6 0
4 years ago
What is the ph of a 2.00 m hno2 solution if ka=5.00 e-6?
zysi [14]

Answer: -

2.5

Explanation: -

Initial [HNO₂] = 2.00 M

ka = 5.00 x 10 ⁻⁶

ICE table for HNO₂ =

[\left[\begin{array}{cccc}concentrations&HNO2&H+&NO2\\Initial&2.00&0&0\\Change&-x&+x&+x\\Equilibrium&2.00-x&x&x\end{array}\right]

Ka = \frac{x2}{2.00-x}

5.00 x 10-6 = \frac{x2}{2.00-x}

x = 0.0032 M

pH = - log [H⁺]

= - log 0.0032

= 2.5

6 0
3 years ago
How do I solve for V1 in this equation ​
arlik [135]

Answer:

<h2>V_{1} = \frac{P_{2}V_{2}T_{1}}{P_{1}T_{2}}</h2>

Explanation:

\frac{P_{1} V_{1}}{T_{1}} = \frac{P_{2}V_{2}}{T_{2}}

<u>First of all cross multiply</u>

That's

P_{1}V_{1}T_{2} = P_{2}V_{2}T_{1}

<u>Next divide both sides by </u>P_{1}T_{2}<u>  in order to isolate </u>V_{1}

We have

\frac{P_{1}V_{1}T_{2}}{P_{1}T_{2}} = \frac{P_{2}V_{2}T_{1}}{P_{1}T_{2}}

We have the final answer as

V_{1} = \frac{P_{2}V_{2}T_{1}}{P_{1}T_{2}}

Hope this helps you

3 0
4 years ago
Lab reaction rate project for chemistry edge2020
guajiro [1.7K]

Answer:

What Affects Reaction Rate?

The purpose of this lab was to see how temperature and particle size affects reaction rate. The first hypothesis is if you increase the temperature of a reaction, then the reaction rate will increase because particles experience more collisions at higher temperatures.The second hypothesis is if you decrease the particle size of a reactant, then the reaction rate will increase because more of the reactants’ molecules will contact each other. The independent variables are particle size and temperature. The dependent variable is reaction rate.

Materials

250 mL graduated cylinder

Thermometer

Water

Timer

Four 250 mL beakers

Seven 1,000 mg effervescent tablets

Two pieces of filter paper

600 mL beaker

Ice

Hot plate

Procedure

Step 1:Gather Materials

Variation of Temperature

Step 2:Measure the Reaction Rate at ≈ 20°C (Room Temperature)

a) Using a graduated cylinder, fill a 250 mL beaker with 200 mL of water.

b) Measure the temperature of the water and record it in the correct row of Table A.

c) Reset the timer. Start the timer as you place a full tablet into the beaker.

d) Record the reaction time on the Data Sheet in the correct row of Table A.

e) Compute the reaction rate to the nearest mg/L/sec. Record it in the last column of Table A. Measure the Reaction Rate at ≈ 40°C

Step 3:Repeat Step 2, heating the water to approximately 40°C using a hot plate during sub-step a. Measure the Reaction Rate at ≈ 65°C

Step 4:Repeat Step 2, heating the water to approximately 65°C using a hot plate during sub-step a. Measure the Reaction Rate at ≈ 5°C

Step 5:Repeat Step 2, chilling the water to approximately 5°C inside an ice bath during sub-step a. (To create an ice bath, place 100 mL of ice and 100 mL of water in a 600 mL beaker of ice water and wait until the temperature reaches approximately 5°C. To save time, you may wish to set up the ice bath, using an additional 250 mL beaker, while working on Step 4.)

Variation of Particle Size

Step 6:Measure the Reaction Rate for a Full Tablet

a) Using a graduated cylinder, fill a 250 mL beaker with 200 mL of water.

b) Reset the timer. Start the timer as you place the tablet in the beaker.

c) Record the reaction time on the Data Sheet in the appropriate row of Table B.

d) Compute the reaction rate to the nearest mg/L/sec. Record it in the last column of Table B.

Step 7:Measure the Reaction Rate for a Partially Broken Tablet

Repeat Step 6, but this time break the tablet into eight small pieces on a piece of filter paper. Make sure to place all of the pieces into the beaker at the same time.

Step 8:Measure the Reaction Rate for a Crushed Tablet

Repeat Step 6, but this time crush the tablet into tiny pieces on a piece of filter paper. Make sure to place all of the pieces into the beaker at the same time.

Step 9: Dispose of all samples according to your teacher’s directions.

Measured Reaction Temperature (°C)

Mass of Tablet (mg)

Volume of Water (L)

Reaction Time (s)

Reaction Rate (mg/L/s)

≈20°C

24

1,000

0.2

34.2

146.2

≈40°C

40

1,000

0.2

26.3

190.1

≈65°C

65

1,000

0.2

14.2

352.1

≈5°C

3

1,000

0.2

138.5

36.1

Relative Particle Size (Small, Medium, Large)

Mass of Tablet (mg)

Volume of Water (L)

Reaction Time (s)

Reaction Rate (mg/L/s)

Full Tablet

large

1,000

0.2

34.5

144.9

Broken Tablet

medium

1,000

0.2

28.9

173.0

Crushed Tablet

small

1,000

0.2

23.1

216.5

The data in the first table show that as the temperature increases the reaction time decreases and in turn the reaction rate increases. The data supported the hypothesis that as temperature increases reaction rate will also increase. The second table shows that as the particle size decreases the reaction time increases because there is more surface area when the particles are smaller. The data in the second table supported the second hypothesis that as particle size decreases the reaction rate will increase because there will be more contact in the molecules. Possible source of error would be an error in stopping the timer in time or chips in the tablets. To improve this lab it could be done with different types of reactions or different temperature or different particle sizes.

Explanation:

6 0
3 years ago
Read 2 more answers
17 moles of oxygen is equal to
mixas84 [53]

Answer:

271.9897999999996

Explanation:

have a good day :)

3 0
3 years ago
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