Answer:
3
Explanation:
Order of in the mass action law is the coefficient which is raised to the active concentration of the reactants. It is experimentally determined and can be zero, positive negative or fractional.
The order of the whole reaction is the sum of the order of each reactant which is raised to its power in the rate law.
Thus,
For the reaction:-
2Mg+O₂→2MgO
Rate = k[Mg][O₂]²
Order w.r.t. Mg = 1
Order w.r.t. O₂ = 2
<u>So, order of the overall reaction = 1 + 2 = 3</u>
In dilute solutions, the unit osmolarity is being used. It usually has units milliosmols per liter of solution or mOsmol/L. An osmole defines the number of moles of the solute that would have an effect on the osmotic pressure of the solution. Osmolarity is calculated by the product of the molarity and the number of particles in the solution which is 2 for potassium chloride. We calculate as follows:
Osmolarity = molarity (# of particles)250 mosmol/L ( 1 osmol / 1000 osmol) = x moles / .100 L (2)
x moles = 0.0125 mol KCl
mass KCl = 0.0125 mol KCl ( 39 + 35.5 g/mol) = 0.93125 g KCl
The statement that best explains why magnesium and chlorine combine in a 1:2 ratio is; Magnesium has two valence electrons, and chlorine can accept one electron in its outer shell.
The number of electrons that an atom of an element has in its outermost shell determines the chemical formula of the compounds formed by atoms such elements.
Magnesium is in group 2, as such it has two electrons in its outermost shell while chlorine in group 17 only accepts one electron in its outermost shell. This one electron will give chlorine an inert gas configuration while the loss of two electrons give magnesium an inert gas configuration.
Therefore; The compound MgCl2 is formed in the ratio of 1:2 because Magnesium has two valence electrons, and chlorine can accept one electron in its outer shell.
Learn more: brainly.com/question/11527546
Answer:
2 HC₂H₃O₂(aq) + Sr(OH)₂(aq) ⇒ Sr(C₂H₃O₂)₂(aq) + 2 H₂O
Explanation:
Let's consider the reaction between acetic acid and strontium hydroxide. This is a neutralization reaction, in which an acid reacts with a base to form salt and water. The unbalanced equation is:
HC₂H₃O₂(aq) + Sr(OH)₂(aq) ⇒ Sr(C₂H₃O₂)₂(aq) + H₂O
We have 1 acetate ion to the left and 2 to the right, so we will multiply HC₂H₃O₂(aq) by 2.
2 HC₂H₃O₂(aq) + Sr(OH)₂(aq) ⇒ Sr(C₂H₃O₂)₂(aq) + H₂O
Finally, we multiply water by 2 to get the balanced equation.
2 HC₂H₃O₂(aq) + Sr(OH)₂(aq) ⇒ Sr(C₂H₃O₂)₂(aq) + 2 H₂O
